Charges of +103×10−9C are placed at each of the four corners of a square of

Question

Charges of

+ \frac{10}{3} \times 10^{- 9} C

are placed at each of the four corners of a square of side 8 cm. The potential at the intersection of the diagonals is

Options:

A . 150√2 volt

B . 1500√2 volt

C . 900√2 volt

D . 900 volt

Answer: Option B
:
B
Potential at the centre O,

V = 4 \times \frac{1}{4 π ϵ_{0}} . \frac{Q}{\frac{a}{\sqrt{2}}}

where

Q = \frac{10}{3} \times 10^{- 9} C

and

a = 8 c m = 8 \times 10^{- 2} m

V = 4 \times 9 \times 10^{9} \times \frac{\frac{10}{3} \times 10^{- 9}}{\frac{8 \times 10^{- 2}}{\sqrt{2}}} = 1500 \sqrt{2}

volt

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