Question
Three charges each of charge ‘q’ are placed at the corners of an equilateral triangle. The fourth charge to be placed at the centre of the triangle so that electrostatic potential energy of the system is zero is
Answer: Option B
:
B
PE=0
314πϵ0q2a+314πϵ0×qx(a√3)=0√3x=−qx=−q√3
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:
B
PE=0
314πϵ0q2a+314πϵ0×qx(a√3)=0√3x=−qx=−q√3
Was this answer helpful ?
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