Two charges + 3.2 × 10 − 19 and − 3.2 × 10 − 19 C placed 2.4 ˙ A apart form an electric dipole. It is placed in a uniform electric field of intensity 4 × 10 5 volt/m. The electric dipole moment is Options: A . &nbsp15.36×10−29 Coulomb×m B . &nbsp15.36×10−19 Coulomb×m C . &nbsp7.68×10−29 Coulomb×m D . &nbsp7.68×10−19 Coulomb×m

Answer: Option C : C Dipole moment p = q (d) = 3.2 × 10 − 19 × ( 2.4 × 10 − 10 ) = 7.68 × 10 − 29 C − m

Two charges +3.2×10−19 and −3.2×10−19 C placed&#x

Question

Two charges

+ 3.2 \times 10^{- 19}

and

- 3.2 \times 10^{- 19}

C placed

2.4 ˙ A

apart form an electric dipole. It is placed in a uniform electric field of intensity

4 \times 10^{5}

volt/m. The electric dipole moment is

Options:

A . 15.36×10−29 Coulomb×m

B . 15.36×10−19 Coulomb×m

C . 7.68×10−29 Coulomb×m

D . 7.68×10−19 Coulomb×m

Answer: Option C
:
C
Dipole moment p = q (d)

= 3.2 \times 10^{- 19} \times (2.4 \times 10^{- 10}) = 7.68 \times 10^{- 29} C - m

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