Question
The perimeter of a triangle is 20 and the points (-2, -3) and (-2, 3) are two of the vertices of it. Then the locus of third vertex is :
Answer: Option C
:
C
A(−2,−3),B(−2,3)
Let the third vertex be C(x,y)
AB + BC+CA=20
BC+CA=14
So locus of C is ellipse with A,B as focii.
2a=14
2ae=6
e=37
∴ we get b as √40
∴ Equation of ellipse is (x+2)240+y249=1
Was this answer helpful ?
:
C
A(−2,−3),B(−2,3)
Let the third vertex be C(x,y)
AB + BC+CA=20
BC+CA=14
So locus of C is ellipse with A,B as focii.
2a=14
2ae=6
e=37
∴ we get b as √40
∴ Equation of ellipse is (x+2)240+y249=1
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution