Question
The locus of the middle points of chords of hyperbola 3x2−2y2+4x−6y=0 parallel to y = 2x, is
Answer: Option A
:
A
By T = S1, the equation of chord whose mid-point is (α,β) is 3xα−2yβ+(x+α)−2(y+β)=0
⇒ x(3α+2)−y(2β+3)=2
as it is parallel to y = 2x
∴ 3α–4β=4
∴ Required locus is 3x – 4y = 4
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:
A
By T = S1, the equation of chord whose mid-point is (α,β) is 3xα−2yβ+(x+α)−2(y+β)=0
⇒ x(3α+2)−y(2β+3)=2
as it is parallel to y = 2x
∴ 3α–4β=4
∴ Required locus is 3x – 4y = 4
Was this answer helpful ?
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