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Question
The equation of a hyperbola, conjugate to the hyperbola x2+3xy+2y2+2x+3y+1=0, is
Options:
A .  Â x2+3xy+2y2+2x+3y+1=0
B .  x2+3xy+2y2+2x+3y+2=0
C .  Â x2+3xy+2y2+2x+3y+3=0
D .  x2+3xy+2y2+2x+3y+4=0
Answer: Option B
:
B
We know that,
Equation of hyperbola + Equation of conjugate
hyperbola = 2(Equation of asymptotes)
Equation of conjugate hyperbola
= 2 Equation of asymptotes - Equation of hyperbola
C(x, y) = 2A(x, y) – H(x, y) …… (i)
H(x,y)x2+3xy+2y2+2x+3y=0
Equation of asymptotes is
x2+3xy+2y2+2x+3y+λ=0
Δ=0,abc+2fghaf2bg2ch2=0,thenλ=1
A(x,y)x2+3xy+2y2+2x+3y+1=0
C(x,y)x2+3xy+2y2+2x+3y+2=0[from equation (i)]

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