If PSQ is a focal chord of the ellipse 16x2+25y2=400 such that SP = 8

Question

If PSQ is a focal chord of the ellipse

16 x^{2} + 25 y^{2} = 400

such that SP = 8 then the length of SQ =

Options:

A . 2

B . 113

C . 16

D . 25

Answer: Option A
:
A

\frac{1}{S P} + \frac{1}{S Q} = \frac{2 a}{b^{2}}

a= 5
b=4
Solving we get,
SQ=2.

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