Question
The intensity of x-rays from Coolidge tube is plotted against wavelength λ for a molybdenum target at an accelerating voltage of 35 kV. The minimum wavelength found is λ0 and the wavelength of the Kα line is λKα. As the accelerating voltage is increased from 35 kV to 70 kV -
Answer: Option A
:
A
The Kα peak corresponds to radiation when the atom transitions between two energy levels due to an internal jump of an electron from the Lshell to the Kshell. It is characteristic for a particular element and will not depend on any external parameters, like the accelerating potential.
But increasing the accelerating potential from 35kV to 70kV will now allow x-rays carrying energies in the range 35-70 eV, which was not allowed earlier. There will now be a higher cut-off on the energy, and hence, a lower cutoff on the wavelength (since E∞1λ). The new cut-off wavelength λ0 will be lower than λ0, and farther from λKα.
Thus, among the given options, the only thing that will change when you increase the accelerationg potential is that (λKα−λ0) will increase.
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:
A
The Kα peak corresponds to radiation when the atom transitions between two energy levels due to an internal jump of an electron from the Lshell to the Kshell. It is characteristic for a particular element and will not depend on any external parameters, like the accelerating potential.
But increasing the accelerating potential from 35kV to 70kV will now allow x-rays carrying energies in the range 35-70 eV, which was not allowed earlier. There will now be a higher cut-off on the energy, and hence, a lower cutoff on the wavelength (since E∞1λ). The new cut-off wavelength λ0 will be lower than λ0, and farther from λKα.
Thus, among the given options, the only thing that will change when you increase the accelerationg potential is that (λKα−λ0) will increase.
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