Question
The Kα x-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atom with a K electron knocked out is 23.32 keV, what will be the energy of this atom when an L electron is knocked out? If required, take hc = 1242 eV.nm.
Answer: Option B
:
B
In our notation of energy levels, an energy EX will mean the energy of the atom when there's a missing electron in the Xshell ( X = K, L, M, N,....). Writing quantitatively.
E(Kα) = EK−EL
⇒EL=EK−E(Kα)
⇒EL=EK−(hcλKα)
⇒EL=23.32keV−(1242eV.nm0.071nm)=23.32keV−17.5eV
⇒EL=5.82keV.
Was this answer helpful ?
:
B
In our notation of energy levels, an energy EX will mean the energy of the atom when there's a missing electron in the Xshell ( X = K, L, M, N,....). Writing quantitatively.
E(Kα) = EK−EL
⇒EL=EK−E(Kα)
⇒EL=EK−(hcλKα)
⇒EL=23.32keV−(1242eV.nm0.071nm)=23.32keV−17.5eV
⇒EL=5.82keV.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution