Question
The anti – derivative of the function (3x + 4) |sin x|, when 0<x<π, is given by
Answer: Option A
:
A
In the interval (0,π), sin x is positive, therefore, (3x+4)|sinx|=(3x+4)sinx.
∴ The antiderivative of (3x+4)|sinx| is
=∫(3x+4)sinxdx=−(3x+4)cosx+∫3cosxdx=−(3x+4)cosx+3sinx+c
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:
A
In the interval (0,π), sin x is positive, therefore, (3x+4)|sinx|=(3x+4)sinx.
∴ The antiderivative of (3x+4)|sinx| is
=∫(3x+4)sinxdx=−(3x+4)cosx+∫3cosxdx=−(3x+4)cosx+3sinx+c
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