Question
Primitive of f(x)=x.2In(x2+1) with respect to x is
Answer: Option C
:
C
I=∫x2In(x2+1)dx let x2+1=t;xdx=dt2
Hence I=12∫2Intdt=12∫tIn2dt=12.tIn2+1In2+1+C=12.(x2+1)In2+1In2+1+C
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:
C
I=∫x2In(x2+1)dx let x2+1=t;xdx=dt2
Hence I=12∫2Intdt=12∫tIn2dt=12.tIn2+1In2+1+C=12.(x2+1)In2+1In2+1+C
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