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Question
Primitive of f(x)=x.2In(x2+1) with respect to x  is
Options:
A .  2In(x2+1)(x2+1)+C
B .  (x2+1)2In(x2+1)In2+1+C
C .  (x2+1)In2+12(In2+1)+C
D .  (x2+1)In22(In2+1)+C
Answer: Option C
:
C
I=x2In(x2+1)dx let x2+1=t;xdx=dt2
Hence I=122Intdt=12tIn2dt=12.tIn2+1In2+1+C=12.(x2+1)In2+1In2+1+C

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