Question
∫x4+11+x6 dx=
Answer: Option D
:
D
I=∫x4+11+x6dx=∫(x4−x2+1)+x2(1+x6)dx=∫x4−x2+11+x6dx+∫x21+x6dx=∫11+x2dx+13∫3x21+x6dx=tan−1(x)+13tan−1x3+c
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:
D
I=∫x4+11+x6dx=∫(x4−x2+1)+x2(1+x6)dx=∫x4−x2+11+x6dx+∫x21+x6dx=∫11+x2dx+13∫3x21+x6dx=tan−1(x)+13tan−1x3+c
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