Question
∫dxcos(2x)cos(4x)is equal to
Answer: Option A
:
A
∫sin(4x−2x)dxsin(2x)cos(2x)cos(4x)=∫sin(4x)dxsin(2x)cos(4x)−∫sec2xdx=2∫cos2xdxcos4x−12(log|sec2x+tan2x|)
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:
A
∫sin(4x−2x)dxsin(2x)cos(2x)cos(4x)=∫sin(4x)dxsin(2x)cos(4x)−∫sec2xdx=2∫cos2xdxcos4x−12(log|sec2x+tan2x|)
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