Question
limx→02sinx−sin2xx3 is equal to
Answer: Option A
:
A
limx→02sinx−sin2xx3
=limx→02sinx(1−cosx)(1+cosx)x3(1+cosx)
=limx→02sin3xx3×11+cosx
=2×(1)3×11+1=1
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:
A
limx→02sinx−sin2xx3
=limx→02sinx(1−cosx)(1+cosx)x3(1+cosx)
=limx→02sin3xx3×11+cosx
=2×(1)3×11+1=1
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