Let A0A1A2A3A4A5 be a regular hexagon inscribed in a circle of unit radius. Then the product of the lengths of the line segments A0A1, A0A2 and A0A4 is
Options:
A .  34
B .  3√3
C .  3
D .  3√32
Answer: Option C : C (c) Each triangle is an equilateral triangle Hence A0A1 = 1 A0A20 =A0A21 +A1A20 - 2A0A1A1A2 cos 120∘ = 1 + 1 - 2.1.1(-12) = 3 ⇒A0A2 = √3 =A0A4 ∴A0A1×A0A2×A0A4 = 1.√3.√3
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