Question
In the given figure, EADF is a rectangle and ABC is a triangle whose vertices lie on the sides of EADF. AE = 22, BE =16, CF = 16, CF = 16 and BF = 2. Find the length of the line joining the
mid-points of the sides AB and BC.
(CAT 1997)
mid-points of the sides AB and BC.
(CAT 1997)
Answer: Option B
:
B
Option (b)
EF = AD = 8
(EADF is a rectangle)
CD = (22 – 16) = 6
So in the right angled triangle ADC, AD = 8 and CD = 6.
Therefore AC = 10
Therefore length of the line joining the mid – points of
AB and BC = 12 (10) = 5
(length of the line joining the mid – point of two sides of a triangle is half the 3\(^{rd}\)
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:
B
Option (b)
EF = AD = 8
(EADF is a rectangle)
CD = (22 – 16) = 6
So in the right angled triangle ADC, AD = 8 and CD = 6.
Therefore AC = 10
Therefore length of the line joining the mid – points of
AB and BC = 12 (10) = 5
(length of the line joining the mid – point of two sides of a triangle is half the 3\(^{rd}\)
Was this answer helpful ?
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