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ABCD is a rhombus with the diagonals AC and BD intersecting at the origin on the x y plane. The equation of the straight line AD is x + y =1. What is the equation of BC?  (CAT 2000)
Options:
A .  x + y = -1
B .  x – y = -1
C .  x + y = 1
D .  None of these
Answer: Option A
:
A
ABCD Is A Rhombus With The Diagonals AC And BD Intersecting ...
Slope of line AD= -1
Hence, eqn of BC which passes through (0,-1) and (-1,0) and is parallel to x+y=1 is
(y-0)=-1(x+1)
Y=-x-1 ⇒x+y= -1. Option (a)
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