If a x 2 + b x + c = 0 , then x = Options: A . &nbspb±√b2−4ac2a B . &nbsp−b±√b2−ac2a C . &nbsp2c−b±√b2−4ac D . &nbspNone of these

If ax2+bx+c=0, then x =

Question

a x^{2} + b x + c = 0

, then x =

Options:

A . b±√b2−4ac2a

B . −b±√b2−ac2a

C . 2c−b±√b2−4ac

D . None of these

Answer: Option D
:
D
Try making perfect square the given equation by adding and subtracting

\frac{b^{2}}{4 a^{2}}

on solving it we'll find

x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

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