Question
If a,b,c are the roots of the equation x3-4x+24=0, then the equation who’s roots are b+c,c+a and a+b is given by?
Answer: Option D
:
D
Option (d)a+b+c=0 ( coefficient of x2 is 0) therefore b+c=-a a+b=-c and a+c=-bthe equation who’s roots are –a,-b and –c is obtained by replacing x by –x in the equationthe required equation is (-x3)-4(-x)+24 = x3 -4x -24=0.
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:
D
Option (d)a+b+c=0 ( coefficient of x2 is 0) therefore b+c=-a a+b=-c and a+c=-bthe equation who’s roots are –a,-b and –c is obtained by replacing x by –x in the equationthe required equation is (-x3)-4(-x)+24 = x3 -4x -24=0.
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