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 Find 1 + (xy) + (xy)2 + (xy)3 + …… if a= 1+ 2x + 3x2 + 4x3+….. ( -1<a<1) and b= 1+3y + 6y2 + 10y3+…. (-1<b<1)
Options:
A .  (a1/2b1/3) / (a1/2 + b1/3 -1)
B .  (a1/2b1/3) / (a1/2 + b1/3 +1)
C .  (a1/2 + b1/3 +1) / (a1/2b1/3)
D .  (a1/2 + b1/3 -2) / (a1/2b1/3)
E .  (a1/2 + b1/3 +2) / (a1/2b1/3)
Answer: Option A
:
A
Option (a)Assume x=0 and y=0. Then the equation gives a value of 1. Put the values of xand y to get a and b. a=1 and b=1Go from answer options. Only answer option a gives 1

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