Question
Three numbers are chosen at random from 1,2,3....10 without replacement. The probability that the minimum of the chosen numbers in 4 or the maximum is 8 is?
Answer: Option A
:
A
Probability of 4 being the minimum number of the three numbers selected = 6C210C3
Probability of 8 being the maximum number of the three numbers selected = 7C210C3
The probability of 4 being the minimum number and 8 being the maximum number = 310C3
Therefore, required probability is6C210C3 +7C210C3 -310C3 =1140
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:
A
Probability of 4 being the minimum number of the three numbers selected = 6C210C3
Probability of 8 being the maximum number of the three numbers selected = 7C210C3
The probability of 4 being the minimum number and 8 being the maximum number = 310C3
Therefore, required probability is6C210C3 +7C210C3 -310C3 =1140
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