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A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:

Options:
A .  \(\frac{1}{24}day\)
B .  \(\frac{7}{24}day\)
C .  \(3\frac{3}{7}days \)
D .  4 days
Answer: Option C

Formula: If A can do a piece of work in n days, then A's 1 day's work =  \(\frac{1}{n},\)


(A + B + C)'s 1 day's work = \(\left(\frac{1}{24}+\frac{1}{6}+\frac{1}{12}\right)=\frac{7}{24}\)


Formula: If A's 1 day's work = \(\frac{1}{n},\)  then A can finish the work in n days.


So, all the three together will complete the job in \(\frac{24}{7}days=3\frac{3}{7}days \)


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