Question
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:
Answer: Option C
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Formula: If A can do a piece of work in n days, then A's 1 day's work = \(\frac{1}{n},\)
(A + B + C)'s 1 day's work = \(\left(\frac{1}{24}+\frac{1}{6}+\frac{1}{12}\right)=\frac{7}{24}\)
Formula: If A's 1 day's work = \(\frac{1}{n},\) then A can finish the work in n days.
So, all the three together will complete the job in \(\frac{24}{7}days=3\frac{3}{7}days \)
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