A bomber plane moves horizontally with a speed of 500 m/s and a bomb released fr

Question

A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle with the horizontal at which it strikes the ground will be (g=10 m/

s^{2}

)

Options:

A . tan−1(15)

B . tan (15)

C . tan−1(1)

D . tan−1(5)

Answer: Option A
:
A

A Bomber Plane Moves Horizontally With A Speed Of 500 M/s An...

Horizontal component of velocity

v_{x}

= 500 m/s
and vertical components of velocity while striking the ground.

v_{y}

= 0 + 10

\times

10 = 100 m/s

∴

Angle with which it strikes the ground.

θ

{t a n}^{- 1}

(

\frac{v_{y}}{v_{x}}

) =

{t a n}^{- 1}

(

\frac{100}{500}

)

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