Question
The maximum and minimum tension in the string whirling in a circle of radius 2.5 m with constant velocity are in the ratio 5 : 3 then its velocity is
Answer: Option A
:
A
In this problem it is assuemed that particle although moving in a vertical loop but its speed remain constant.
Tenstion at lowest point Tmax = mv2r + mg
Tension at highest point Tmin = mv2r - mg
TmaxTmin = mv2r+mgmv2r−mg = 53
by solving we get , v=√4gr = √4×9.8×2.5 = √98 m/s
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:
A
In this problem it is assuemed that particle although moving in a vertical loop but its speed remain constant.
Tenstion at lowest point Tmax = mv2r + mg
Tension at highest point Tmin = mv2r - mg
TmaxTmin = mv2r+mgmv2r−mg = 53
by solving we get , v=√4gr = √4×9.8×2.5 = √98 m/s
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