The length of second's hand in a watch is 1 cm. The change in velocity of its tip in 15 seconds is Options: A . &nbspZero B . &nbspπ30√2 cm /sec C . &nbspπ30 cm/sec D . &nbspπ√230 cm /sec

Answer: Option D : D In 15 second's hand rotate through 90 ∘ Change in velocity | ¯ △ v | = 2v sin ( θ 2 ) =2(r ω ) sin ( 90 ∘ 2 ) = 2 × 1 × 2 π T × 1 √ 2 = 4 π 60 √ 2 = 4 π 60 √ 2 = π √ 2 c m 30 s e c [As T = 60 sec]

The length of second's hand in a watch is 1 cm. The change in velocity of its ti

Question

The length of second's hand in a watch is 1 cm. The change in velocity of its tip in 15 seconds is

Options:

A . Zero

B . π30√2 cm /sec

C . π30 cm/sec

D . π√230 cm /sec

Answer: Option D
:
D

The Length Of Second's Hand In A Watch Is 1 Cm. The Change I...

In 15 second's hand rotate through

90^{\circ}

Change in velocity |

¯ △ v

| = 2v sin (

\frac{θ}{2}

)
=2(r

ω

) sin (

\frac{90^{\circ}}{2}

) = 2

\times

\times

\frac{2 π}{T}

\times

\frac{1}{\sqrt{2}}

\frac{4 π}{60 \sqrt{2}}

\frac{4 π}{60 \sqrt{2}}

\frac{π \sqrt{2} c m}{30 s e c}

[As T = 60 sec]

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