Question
A body of mass m hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of 60∘ with the vertical. The tension in the string at mean position is
Answer: Option A
:
A
When body is released from the position p (inclined at angle θ from vertical) then velocity at mean position
v = √2gl(1−cosθ)
∴ Tension at the lowest point = mg + mv2l
= mg + ml[2gl(1 - cos 60)] = mg + mg = 2mg
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:
A
When body is released from the position p (inclined at angle θ from vertical) then velocity at mean position
v = √2gl(1−cosθ)
∴ Tension at the lowest point = mg + mv2l
= mg + ml[2gl(1 - cos 60)] = mg + mg = 2mg
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