Question
If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-kr2) , the total energy is
Answer: Option A
:
A
mv2r = kr2 ⇒ m v2 = kr ∴ K.E = 12mv2 = k2r
P.E = ∫F dr = ∫ kr2dr = - kr
∴ Total energy = K.E + P.E = k2r - kr =- k2r
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:
A
mv2r = kr2 ⇒ m v2 = kr ∴ K.E = 12mv2 = k2r
P.E = ∫F dr = ∫ kr2dr = - kr
∴ Total energy = K.E + P.E = k2r - kr =- k2r
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