Question
2Fe(s) + 32 O2(g)→Fe2O3(s) (△H=−193.4kJ) ......(1)
Mg(s) + 12 O2(g)→MgO(s) (△H=−140.2kJ) ......(2)
What is △∆H of the reaction? 3Mg + Fe2O3→3MgO + 2Fe
Mg(s) + 12 O2(g)→MgO(s) (△H=−140.2kJ) ......(2)
What is △∆H of the reaction? 3Mg + Fe2O3→3MgO + 2Fe
Answer: Option D
:
D
Equation (2) is multiplied by 3
2Fe(s)+32O2(g)→Fe2O3(s)△H=−193.4kJ......(1)
3Mg(s)+32O2(g)→3MgO(s)△H=−420.6kJ......(3)
Subtracting equation (1) from (3)
3Mg(s)+Fe2O3→3MgO+2Fe△H=−420.6−(−193.4)
= -227.2 kJ
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:
D
Equation (2) is multiplied by 3
2Fe(s)+32O2(g)→Fe2O3(s)△H=−193.4kJ......(1)
3Mg(s)+32O2(g)→3MgO(s)△H=−420.6kJ......(3)
Subtracting equation (1) from (3)
3Mg(s)+Fe2O3→3MgO+2Fe△H=−420.6−(−193.4)
= -227.2 kJ
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