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2Fe(s) + 32 O2(g)Fe2O3(s)    (H=193.4kJ)      ......(1)
Mg(s) + 12 O2(g)MgO(s)    (H=140.2kJ)      ......(2)
What is ∆H of the reaction? 3Mg + Fe2O33MgO + 2Fe
Options:
A .  -272.3 kJ
B .  272.3 kJ
C .  272.2 kJ
D .  -227.2 kJ
Answer: Option D
:
D
Equation (2) is multiplied by 3
2Fe(s)+32O2(g)Fe2O3(s)H=193.4kJ......(1)
3Mg(s)+32O2(g)3MgO(s)H=420.6kJ......(3)
Subtracting equation (1) from (3)
3Mg(s)+Fe2O33MgO+2FeH=420.6(193.4)
= -227.2 kJ

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