Quantitative Aptitude
TRAINS MCQs
Problems On Trains
Total Questions : 842
| Page 8 of 85 pages
Answer: Option C. -> 245 m
 - Speed = 45 x 5 m/sec = 25 m/sec. 18 2
Time = 30 sec.
Let the length of bridge be x metres.
Then, 130 + x = 25 30 2
2(130 + x) = 750
x = 245 m.
 - Speed = 45 x 5 m/sec = 25 m/sec. 18 2
Time = 30 sec.
Let the length of bridge be x metres.
Then, 130 + x = 25 30 2
2(130 + x) = 750
x = 245 m.
Answer: Option C. -> 3 : 2
 - Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y = 23 x+ y
27x + 17y = 23x + 23y
4x = 6y
x = 3 . y 2
 - Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y = 23 x+ y
27x + 17y = 23x + 23y
4x = 6y
x = 3 . y 2
Answer: Option B. -> 240 m
 - Speed = 54 x 5 m/sec = 15 m/sec. 18
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, x + 300 = 15 36
x + 300 = 540
x = 240 m.
 - Speed = 54 x 5 m/sec = 15 m/sec. 18
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, x + 300 = 15 36
x + 300 = 540
x = 240 m.
Answer: Option B. -> 89 sec
 - Speed = 240 m/sec = 10 m/sec. 24
Required time = 240 + 650 sec = 89 sec. 10
 - Speed = 240 m/sec = 10 m/sec. 24
Required time = 240 + 650 sec = 89 sec. 10
Answer: Option A. -> 50 m
 - Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= 10 x 5 m/sec 18 = 25 m/sec 9
2x = 25 36 9
2x = 100
x = 50.
 - Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= 10 x 5 m/sec 18 = 25 m/sec 9
2x = 25 36 9
2x = 100
x = 50.
Answer: Option A. -> 40 sec
 - Formula for converting from km/hr to m/s: X km/hr = X x 5 m/s. 18
Therefore, Speed = 45 x 5 m/sec = 25 m/sec. 18 2 Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = Distance Speed
Required time = 500 x 2 sec = 40 sec. 25
 - Formula for converting from km/hr to m/s: X km/hr = X x 5 m/s. 18
Therefore, Speed = 45 x 5 m/sec = 25 m/sec. 18 2 Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = Distance Speed
Required time = 500 x 2 sec = 40 sec. 25
Answer: Option C. -> 48 sec
 - Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18
= 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125
 - Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18
= 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125
Answer: Option A. -> 3501
Answer: Option B. -> 250 meters
Answer: Option D. -> 14 seconds