Question
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option C
 - Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18
= 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125
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 - Relative speed = (60+ 90) km/hr
= 150 x 5 m/sec 18
= 125 m/sec. 3 Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = 2000 x 3 sec = 48 sec. 125
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