Quantitative Aptitude
TRAINS MCQs
Problems On Trains
Total Questions : 842
| Page 7 of 85 pages
Answer: Option D. -> 10.8
 - Relative speed = (60 + 40) km/hr = 100 x 5 m/sec = 250 m/sec. 18 9
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = 300 x 9 sec = 54 sec = 10.8 sec. 250 5
 - Relative speed = (60 + 40) km/hr = 100 x 5 m/sec = 250 m/sec. 18 9
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = 300 x 9 sec = 54 sec = 10.8 sec. 250 5
Answer: Option B. -> 6 sec
 - Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
= 66 x 5 m/sec 18 = 55 m/sec. 3 Time taken to pass the man = 110 x 3 sec = 6 sec. 55
 - Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
= 66 x 5 m/sec 18 = 55 m/sec. 3 Time taken to pass the man = 110 x 3 sec = 6 sec. 55
Answer: Option B. -> 3 min
 - Total distance covered = 7 + 1 miles 2 4 = 15 miles. 4 Time taken = 15 hrs 4 x 75 = 1 hrs 20 = 1 x 60 min. 20
= 3
 - Total distance covered = 7 + 1 miles 2 4 = 15 miles. 4 Time taken = 15 hrs 4 x 75 = 1 hrs 20 = 1 x 60 min. 20
= 3
Answer: Option C. -> 500
 - Speed = 78 x 5 m/sec = 65 m/sec. 18 3
Time = 1 minute = 60 seconds.
Let the length of the tunnel be x metres.
Then, 800 + x = 65 60 3
3(800 + x) = 3900
x = 500
 - Speed = 78 x 5 m/sec = 65 m/sec. 18 3
Time = 1 minute = 60 seconds.
Let the length of the tunnel be x metres.
Then, 800 + x = 65 60 3
3(800 + x) = 3900
x = 500
Answer: Option B. -> 350 m
 - Speed = 300 m/sec = 50 m/sec. 18 3
Let the length of the platform be x metres.
Then, x + 300 = 50 39 3
3(x + 300) = 1950
x = 350 m
 - Speed = 300 m/sec = 50 m/sec. 18 3
Let the length of the platform be x metres.
Then, x + 300 = 50 39 3
3(x + 300) = 1950
x = 350 m
Answer: Option B. -> 150 m
 - Let the length of the train be x metres and its speed by y m/sec.
Then, x = 15 y = x . y 15
x + 100 = x 25 15
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m
 - Let the length of the train be x metres and its speed by y m/sec.
Then, x = 15 y = x . y 15
x + 100 = x 25 15
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m
Answer: Option D. -> 79.2 km/hr
 - Let the length of the train be x metres and its speed by y m/sec.
Then, x = 8 x = 8y y Now, x + 264 = y 20
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5
 - Let the length of the train be x metres and its speed by y m/sec.
Then, x = 8 x = 8y y Now, x + 264 = y 20
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5
Answer: Option B. -> 30
 - Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr = 60 x 5 m/sec 18 = 50 m/sec. 3 Time taken to pass the man = 500 x 3 sec 50
= 30 sec.
 - Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr = 60 x 5 m/sec 18 = 50 m/sec. 3 Time taken to pass the man = 500 x 3 sec 50
= 30 sec.
Answer: Option B. -> 150 metres
 - Speed= 60 x 5 m/sec = 50 m/sec. 18 3
Length of the train = (Speed x Time) = 50 x 9 m = 150 m. 3
 - Speed= 60 x 5 m/sec = 50 m/sec. 18 3
Length of the train = (Speed x Time) = 50 x 9 m = 150 m. 3
Answer: Option B. -> 50 km/hr
 - Speed of the train relative to man = 125 m/sec 10
= 25 m/sec. 2
= 25 x 18 km/hr 2 5
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 x = 50 km/hr.
 - Speed of the train relative to man = 125 m/sec 10
= 25 m/sec. 2
= 25 x 18 km/hr 2 5
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 x = 50 km/hr.