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Quantitative Aptitude

TIME AND WORK MCQs

Time & Work, Work And Wages

Total Questions : 1512 | Page 9 of 152 pages
Question 81.
  1. In a company 4 machines are running simultaneously at a constant rate `r’ to produce \(\frac{5}{8}\) of the total order for wrenches. The remaining wrenches needed as per the order are to be produced in 3 hours with all 4 machines running at the same rate `r’. If the cost of operating each machine for one hour is Rs 22.00, find the total cost of machine operation to meet the order.

  1.    Rs 407
  2.    Rs 704
  3.    Rs 740
  4.     none of these
 Discuss Question
Answer: Option B. -> Rs 704

To find the total cost of machine operation to meet the order, we need to calculate the total number of hours required for the 4 machine working together to meet the order.

Given:
4 machines working simultaneously at a constant rate r to produce of the total order for wrenches.
Remaining wrenches needed as per the order are to be produced in 3 hours with all 4 machines running at the same rate r.
Cost of operating each machine for one hour is Rs 22.00

Now, we can calculate the total number of hours required for the 4 machine working together to meet the order.

Let us assume that total number of wrenches needed as per the order isx.

Then,
of x =

4x =

x =

Now, as per the given condition,
Remaining wrenches needed as per the order are to be produced in 3 hours

Remaining wrenches = x

Remaining wrenches =

Now,
Total number of wrenches =

Total number of wrenches = +

Total number of wrenches =

Now, as the 4 machines are working simultaneously at a constant rate r to produce wrenches per hour,

Total number of hours required for the 4 machine working together to meet the order =

Total number of hours required for the 4 machine working together to meet the order =

Therefore, the total cost of machine operation to meet the order is

Total cost of machine operation = Cost of operating each machine for one hour × Total number of hours required for the 4 machine working together to meet the order

Total cost of machine operation = Rs 22.00 × 7

Total cost of machine operation = Rs 704

Hence, the answer is Option B. Rs 704.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 82.
  1. A sum of Rs 77 was paid for a piece of work which A can do in 10 days, B in 15 days, C in 20 days and D in 25 days. Find the share of C, if all of them worked together.

  1.    Rs 12
  2.    Rs 15
  3.    Rs 18
  4.    Rs 21
 Discuss Question
Answer: Option B. -> Rs 15

Let the share of each worker A, B, C and D be a, b, c and d respectively.

According to the question,

We can write the following equations:

a/10 + b/15 + c/20 + d/25 = 77/100 (1)

a+b+c+d = 100 (2)

Solving equation (1) and (2) we get:

a = 40
b = 30
c = 15
d = 5

Hence, the share of C is Rs 15.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 83.

  1. (X + Y + Z) can complete a piece of work in 6 days. If (X + Y) can do the work in 9  days and Y alone in 24 days, find the amount X will receive if the total remuneration for the work is Rs 400.

  1.    Rs 150
  2.    Rs 180
  3.    Rs 200
  4.    Rs 220
 Discuss Question
Answer: Option A. -> Rs 150
Question 84.

  1. A, B and C are employed to do a piece of work for Rs 805. A and B together are supposed to do (19/23) of the work and B and C together (8/23) of the work. What should A be paid?

  1.    Rs 450
  2.    Rs 475
  3.    Rs 500
  4.    Rs 525
 Discuss Question
Answer: Option D. -> Rs 525
Question 85.
  1. 3 men can do as much work as 5 boys. The wages of 3 boys are equal to those of 2 men. A piece of work for which 40 boys and 15 men are employed takes 8 weeks and costs Rs 15750. How long would it take if 20 boys and 20 men were employed and how much would it cost?

  1.    \(65\frac{1}{4} days ,Rs . 15866.25\)
  2.    \(66\frac{1}{4} days ,Rs . 14256.25\)
  3.    \(68\frac{1}{4} days ,Rs . 15356.25\)
  4.     none of these
 Discuss Question
Answer: Option C. -> \(68\frac{1}{4} days ,Rs . 15356.25\)
Let us assume that the efficiency of a man is 'm' and the efficiency of a boy is 'b'.Given,3m = 5b …… (1)3b wages = 2m wagesTherefore, b wages = (2/3)m wagesLet us assume that the total work is 'W' and the time taken to complete the work by 40 boys and 15 men is 'T' weeks.According to the question,40b + 15m = W …… (2)And, 40b wages + 15m wages = Rs 15750 …… (3)We can use equations (1), (2), and (3) to find the value of 'W'.40b + 15m = W40b + 15(m/2)(3/2) = W [Using equation (1)]40b + (45/4)b = W [Substituting m wages = (2/3)b wages]185b/4 = WNow, we can use the formula: Work = Efficiency × Time to find the time taken to complete the work with 20 boys and 20 men.20b + 20m = W …… (4)Let us assume that the time taken is 't' weeks.20b + 20(m/2)(3/2) = W [Using equation (1)]20b + (15/2)b = W [Substituting m wages = (2/3)b wages]35b/2 = WSince the amount of work done is the same in both cases, we can equate equations (2) and (4) to get:40b + 15m = 20b + 20m20b = 5m4b = mNow, we can use the formula: Work = Efficiency × Time to find the value of 't'.20b + 20m = W20b + 20(4b) = (185b/4)100b/4 = (185b/4) - 20b65b/4 = Wt = W / (20b + 20m)t = (65b/4) / (20b + 20(4b))t = (65/4) / (20 + 80)t = (65/4) / 100t = 13/80t = 0.1625 weeksNow, we can find the cost of the work with 20 boys and 20 men using the formula:Cost = Total Wages × Time × RateLet us assume that the rate is 'r' rupees per week per person.Total Wages for 20 boys and 20 men = 20b wages × 20 + 20m wages × 20 = (2/3)m wages × 20 × 20 + m wages × 20 × 20 = 800m wagesCost = 800m wages × 0.1625 weeks × rCost = 130m wages × rSubstituting the value of m wages in terms of b wages, we get:Cost = 130(3b/2) wages × rCost = 195brSubstituting the value of 'r' from equation (3), we get:Cost = 195br = 15750/8r = 15750/(8 × 195b)r = 4.054Now, we can find the cost of the work with 20 boys and 20 men using the formula:Cost = Total Wages × Time × RateTotal Wages forIf you think the solution is wrong then please provide your own solution below in the comments section .
Question 86. A, B and C completed a work costing Rs. 1800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio of 5 : 6 : 4, how much amount will be received by A ?
  1.    Rs. 600
  2.    Rs. 750
  3.    Rs. 800
  4.    Rs. 900
 Discuss Question
Answer: Option A. -> Rs. 600
Question 87. P and Q together can do a job in 6 days. Q and R can finish the same job in $$\frac{{60}}{7}$$ days. P started the work and worked for 3 days. Q and R continued for 6 days to finish the work. Then the difference of days in which R and P can complete the alone is P can complete the job alone is ?
  1.    10 days
  2.    8 days
  3.    12 days
  4.    15 days
 Discuss Question
Answer: Option A. -> 10 days
Question 88. X can do a piece of work in 24 days. When he had worked for 4 days, Y joined him. If complete work was finished in 16 days, Y can alone finish that work in ?
  1.    27 days
  2.    36 days
  3.    42 days
  4.    18 days
 Discuss Question
Answer: Option B. -> 36 days
Question 89. If the expenditure of gas on burning 6 burners for 6 hours a day for 8 days is Rs. 450, then how many burners can be used for 10 days at 5 hours a day for Rs. 625 ?
  1.    12
  2.    16
  3.    4
  4.    8
 Discuss Question
Answer: Option D. -> 8
Question 90. A and B can complete a piece of work in 12 and 18 days respectively. A begins to do the work and they work alternatively one at a time for one day each. The whole work will be completed in ?
  1.    $${\text{14}}\frac{1}{3}{\text{ days}}$$
  2.    $${\text{15}}\frac{2}{3}{\text{ days}}$$
  3.    $${\text{16}}\frac{1}{3}{\text{ days}}$$
  4.    $${\text{18}}\frac{2}{3}{\text{ days}}$$
 Discuss Question
Answer: Option A. -> $${\text{14}}\frac{1}{3}{\text{ days}}$$

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