Quantitative Aptitude
TIME AND WORK MCQs
Time & Work, Work And Wages
- In a company 4 machines are running simultaneously at a constant rate `r’ to produce \(\frac{5}{8}\) of the total order for wrenches. The remaining wrenches needed as per the order are to be produced in 3 hours with all 4 machines running at the same rate `r’. If the cost of operating each machine for one hour is Rs 22.00, find the total cost of machine operation to meet the order.
To find the total cost of machine operation to meet the order, we need to calculate the total number of hours required for the 4 machine working together to meet the order.
Given:
4 machines working simultaneously at a constant rate r to produce of the total order for wrenches.
Remaining wrenches needed as per the order are to be produced in 3 hours with all 4 machines running at the same rate r.
Cost of operating each machine for one hour is Rs 22.00
Now, we can calculate the total number of hours required for the 4 machine working together to meet the order.
Let us assume that total number of wrenches needed as per the order is ‘x’.
Then,
of x =
⇒ 4x =
⇒ x =
Now, as per the given condition,
Remaining wrenches needed as per the order are to be produced in 3 hours
⇒ Remaining wrenches = x –
⇒ Remaining wrenches =
Now,
Total number of wrenches =
⇒ Total number of wrenches = +
⇒ Total number of wrenches =
Now, as the 4 machines are working simultaneously at a constant rate r to produce wrenches per hour,
Total number of hours required for the 4 machine working together to meet the order =
⇒ Total number of hours required for the 4 machine working together to meet the order =
Therefore, the total cost of machine operation to meet the order is
Total cost of machine operation = Cost of operating each machine for one hour × Total number of hours required for the 4 machine working together to meet the order
⇒ Total cost of machine operation = Rs 22.00 × 7
⇒ Total cost of machine operation = Rs 704
Hence, the answer is Option B. Rs 704.
If you think the solution is wrong then please provide your own solution below in the comments section .
Let the share of each worker A, B, C and D be a, b, c and d respectively.
According to the question,
We can write the following equations:
a/10 + b/15 + c/20 + d/25 = 77/100 (1)
a+b+c+d = 100 (2)
Solving equation (1) and (2) we get:
a = 40
b = 30
c = 15
d = 5
Hence, the share of C is Rs 15.
If you think the solution is wrong then please provide your own solution below in the comments section .
Let us assume that the efficiency of a man is 'm' and the efficiency of a boy is 'b'.Given,3m = 5b …… (1)3b wages = 2m wagesTherefore, b wages = (2/3)m wagesLet us assume that the total work is 'W' and the time taken to complete the work by 40 boys and 15 men is 'T' weeks.According to the question,40b + 15m = W …… (2)And, 40b wages + 15m wages = Rs 15750 …… (3)We can use equations (1), (2), and (3) to find the value of 'W'.40b + 15m = W40b + 15(m/2)(3/2) = W [Using equation (1)]40b + (45/4)b = W [Substituting m wages = (2/3)b wages]185b/4 = WNow, we can use the formula: Work = Efficiency × Time to find the time taken to complete the work with 20 boys and 20 men.20b + 20m = W …… (4)Let us assume that the time taken is 't' weeks.20b + 20(m/2)(3/2) = W [Using equation (1)]20b + (15/2)b = W [Substituting m wages = (2/3)b wages]35b/2 = WSince the amount of work done is the same in both cases, we can equate equations (2) and (4) to get:40b + 15m = 20b + 20m20b = 5m4b = mNow, we can use the formula: Work = Efficiency × Time to find the value of 't'.20b + 20m = W20b + 20(4b) = (185b/4)100b/4 = (185b/4) - 20b65b/4 = Wt = W / (20b + 20m)t = (65b/4) / (20b + 20(4b))t = (65/4) / (20 + 80)t = (65/4) / 100t = 13/80t = 0.1625 weeksNow, we can find the cost of the work with 20 boys and 20 men using the formula:Cost = Total Wages × Time × RateLet us assume that the rate is 'r' rupees per week per person.Total Wages for 20 boys and 20 men = 20b wages × 20 + 20m wages × 20 = (2/3)m wages × 20 × 20 + m wages × 20 × 20 = 800m wagesCost = 800m wages × 0.1625 weeks × rCost = 130m wages × rSubstituting the value of m wages in terms of b wages, we get:Cost = 130(3b/2) wages × rCost = 195brSubstituting the value of 'r' from equation (3), we get:Cost = 195br = 15750/8r = 15750/(8 × 195b)r = 4.054Now, we can find the cost of the work with 20 boys and 20 men using the formula:Cost = Total Wages × Time × RateTotal Wages forIf you think the solution is wrong then please provide your own solution below in the comments section .