12th Grade > Mathematics
STATISTICS AND COLLECTION OF STATISTICAL DATA MCQs
Statistics, Introduction To Statistics, Collection Of Data (11th And 12th Grade)
Total Questions : 105
| Page 9 of 11 pages
Answer: Option C. -> Team A is more consistent than team B.
:
C
We know that, lesser is the coefficient of variation, the data is more consistent.
Since C.V. of the team A is 2.5, which is less than the C.V. of team B, we can conclude that team A is more Consistent.
:
C
We know that, lesser is the coefficient of variation, the data is more consistent.
Since C.V. of the team A is 2.5, which is less than the C.V. of team B, we can conclude that team A is more Consistent.
Answer: Option C. -> 57 kg
:
C
Total weight of 7 students is =55×7=385kg
Sum of weight of 6 students
=52+58+55+53+56+54=328kg
∴Weight of seventh student =385–328=57kg.
:
C
Total weight of 7 students is =55×7=385kg
Sum of weight of 6 students
=52+58+55+53+56+54=328kg
∴Weight of seventh student =385–328=57kg.
Answer: Option A. -> less than 3
:
A
¯x=−1+0+43=1.∴Mean Deviation =13[|−1−1|+|0−1|+|4−1|]=2
:
A
¯x=−1+0+43=1.∴Mean Deviation =13[|−1−1|+|0−1|+|4−1|]=2
Answer: Option C. -> √3
:
C
Given that median = 4 and mode = 6. We know that
Mean - mode = 3 (Mean - Median)
Mean - 6 = 3 (Mean - 4)
¯x−6=3¯x−12
¯x=3
σ2=∑x2in−(∑xin)2=484−(3)2=3 ∴σ=√3
:
C
Given that median = 4 and mode = 6. We know that
Mean - mode = 3 (Mean - Median)
Mean - 6 = 3 (Mean - 4)
¯x−6=3¯x−12
¯x=3
σ2=∑x2in−(∑xin)2=484−(3)2=3 ∴σ=√3
Answer: Option C. -> 6
:
C
6=3+4+x+7+105
⇒30=24+x
⇒x=6
:
C
6=3+4+x+7+105
⇒30=24+x
⇒x=6
Answer: Option A. -> 16
:
A
Range = Highest observation- Lowest observation
= 19 − 3
= 16
:
A
Range = Highest observation- Lowest observation
= 19 − 3
= 16
Answer: Option C. -> ¯¯¯x+10αα
:
C
Let x1,x2……,xn be n observations.
Then¯¯¯x=1n∑xi
letyi=xiα+10
¯¯¯y=1nn∑iyi
And,¯¯¯y=1n[(n∑ixiα+10.n]
⇒¯¯¯y=1α¯¯¯x+10
=¯¯¯x+10αα.
:
C
Let x1,x2……,xn be n observations.
Then¯¯¯x=1n∑xi
letyi=xiα+10
¯¯¯y=1nn∑iyi
And,¯¯¯y=1n[(n∑ixiα+10.n]
⇒¯¯¯y=1α¯¯¯x+10
=¯¯¯x+10αα.
Answer: Option C. -> 26
:
C
Sum of total number =18×5=90
After one number excluded
Sum of total number =16×4=64
Then, excluded number is 90−64=26
:
C
Sum of total number =18×5=90
After one number excluded
Sum of total number =16×4=64
Then, excluded number is 90−64=26
Answer: Option A. -> α−54
:
A
Arrange the data as: α−72,α−3,α−52,α−2,α−12,α+12,α+4,α+5,
Median =a−2+α−122=2α−522=α−54
:
A
Arrange the data as: α−72,α−3,α−52,α−2,α−12,α+12,α+4,α+5,
Median =a−2+α−122=2α−522=α−54
Answer: Option D. -> 31
:
D
20∑i=1(xi−30)=20=20∑i=1xi−20×30=20
⇒20∑i=1xi=620.Mean=20∑i=120=62020=31.
:
D
20∑i=1(xi−30)=20=20∑i=1xi−20×30=20
⇒20∑i=1xi=620.Mean=20∑i=120=62020=31.
Latest Videos
Latest Test Papers
Login With Google
Old way of Login
Login With Email