12th Grade > Mathematics
STATISTICS AND COLLECTION OF STATISTICAL DATA MCQs
Statistics, Introduction To Statistics, Collection Of Data (11th And 12th Grade)
Total Questions : 105
| Page 6 of 11 pages
Answer: Option A. -> Personal interview
:
A
The possibility of influencing the responder is most in the 'personal interview' mode because there is direct personal interaction involved.
:
A
The possibility of influencing the responder is most in the 'personal interview' mode because there is direct personal interaction involved.
Answer: Option D. -> all of these
:
D
Reliability of sampling data depends on all of the mentioned factors.
:
D
Reliability of sampling data depends on all of the mentioned factors.
Answer: Option B. -> Mailing questionnaire
:
B
In the mailing questionnaire method, since there is no verbal communication between the responder and the enumerator, ambiguous questions cannot be clarified.
:
B
In the mailing questionnaire method, since there is no verbal communication between the responder and the enumerator, ambiguous questions cannot be clarified.
Answer: Option C. -> Once every ten years
:
C
Census of India is carried out once every 10 years.
:
C
Census of India is carried out once every 10 years.
Answer: Option B. -> False
:
B
In the mailed questionnaire method, the respondents need to read and understand the questions and respond appropriately. Hence, this method cannot be used if the respondents are illiterate.
:
B
In the mailed questionnaire method, the respondents need to read and understand the questions and respond appropriately. Hence, this method cannot be used if the respondents are illiterate.
Answer: Option A. -> less than 3
:
A
¯x=−1+0+43=1.∴Mean Deviation=13[|−1−1|+|0−1|+|4−1|]=2
:
A
¯x=−1+0+43=1.∴Mean Deviation=13[|−1−1|+|0−1|+|4−1|]=2
Answer: Option B. -> 20
:
B
C.V=2;σ=0.4(given)C.V=100×s.dmean2=100×0.4meanMean=402=20
:
B
C.V=2;σ=0.4(given)C.V=100×s.dmean2=100×0.4meanMean=402=20
Answer: Option C. -> 4 and 7
:
C
Let the other two numbers be
αandβ.
¯x=4,N=5and∑(x−¯x)2N=5.2⇒∑(x−¯x)2=(5.2)5∴∑(x−¯x)2=26∴(1−4)2+(2−4)2+(6−4)2+(α−4)2+(β−4)2=26∴(α−4)2+(β−4)2=9Also,1+2+6+α+β5=4∴α+β=20−9=11Clearly4,7onlysatisfytheaboveequationinα,β.Hencerequirednumbersare4,7.
:
C
Let the other two numbers be
αandβ.
¯x=4,N=5and∑(x−¯x)2N=5.2⇒∑(x−¯x)2=(5.2)5∴∑(x−¯x)2=26∴(1−4)2+(2−4)2+(6−4)2+(α−4)2+(β−4)2=26∴(α−4)2+(β−4)2=9Also,1+2+6+α+β5=4∴α+β=20−9=11Clearly4,7onlysatisfytheaboveequationinα,β.Hencerequirednumbersare4,7.
Answer: Option A. -> √2
:
A
Here¯x=1+2+3+4+55=3
xx−¯x(x−¯x2)1−242−11300411524∴∑(x−¯x)2=10
∴S.D=σ=√(x−¯x)N=√105=√2
:
A
Here¯x=1+2+3+4+55=3
xx−¯x(x−¯x2)1−242−11300411524∴∑(x−¯x)2=10
∴S.D=σ=√(x−¯x)N=√105=√2
Answer: Option C. -> n(n+1)d(2n+1)
:
C
¯x=2n+12(a+a+2nd))(2n+1)=a+nd∑|x−¯x|=2d(1+2+.....+n)=n(n+1)d∴M.D=n(n+1)d(2n+1)
:
C
¯x=2n+12(a+a+2nd))(2n+1)=a+nd∑|x−¯x|=2d(1+2+.....+n)=n(n+1)d∴M.D=n(n+1)d(2n+1)