Question
A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was
Answer: Option C
Answer: (c)Let the distance be x km.Total time = 5 hours 48 minutes= $5 + 48/60 = (5 + 4/5)$ hours= $29/5$ hours$x/25 + x/4 = 29/5$${4x + 25x}/100 = 29/5$5 × 29x = 29 × 100$x = {29 × 100}/{5 × 29}$ = 20 km. Using Rule 5,If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$
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Answer: (c)Let the distance be x km.Total time = 5 hours 48 minutes= $5 + 48/60 = (5 + 4/5)$ hours= $29/5$ hours$x/25 + x/4 = 29/5$${4x + 25x}/100 = 29/5$5 × 29x = 29 × 100$x = {29 × 100}/{5 × 29}$ = 20 km. Using Rule 5,If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$
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