Steps: 2 Marks
Answer: 1 Mark
Number of runs made by Anish in 6 overs
 = 42
Number of runs made by Anup in 7 overs
=  63
Number of runs made by Anish in 1 overs
= $\frac{42}{6}$ = 7
Number of runs made by Anup in 1 overs
= $\frac{63}{7}$ = 9
Therefore, Anup made more runs per over.
Ratio of their runs made
$\frac{Anish}{Anup}=\frac{42}{63}=\frac{2}{3}\Rightarrow 2:3$

Steps: 2 Marks
Answer: 1 Mark
Marks scored by Aamir = 54
Marks scored by Usha = 100 - 34 = 66
The ratio of the marks of Aamir to Usha = 54 : 66 = 9 : 11
Marks scored by Preeti = 72
Let the marks scored by Kunal be $x$.
$\therefore 72:x=9:11$
$\Rightarrow \frac{72}{x}=\frac{9}{11}$
$\Rightarrow \frac{x}{72}=\frac{11}{9}$
$\Rightarrow x=\frac{72\times 11}{9}=8\times 11$
$\Rightarrow x=88$
$\therefore$ Marks obtained by Kunal is $88$.

Steps: 3 Marks
Answer: 1 Mark
Let the speed of Raj and Alisha be S1 and S2 respectively.

The ratio of the distance of raj's house to the school and Alisha's house to the school $=\frac{D_1}{D_2}=\frac{13}{17}$

Since the time is same, time = T

The ratio of walking speed of Raj and Alisha
$=\frac{S_1}{S_2}$

$\frac{S_1}{S_2}=\frac{D_1.T}{D_2.T}=\frac{13}{17}$
Ratio of walking speed of Raj and Alisha is 13 : 17

Concept: 1 Mark
Application: 1 Mark
Steps: 1 Mark
Solution: 1 Mark
Let x and y be the weight of Meenakshi and Ankur has respectively.
The ratio of the weights of Meenakshi to Ankur  = 13:15
After exercising, ratio of the weights of Meenakshi to Ankur = x :( y-5) = 13:14
Comparing both $\frac{x}{y}$ =  $\frac{13}{15}$  and  $\frac{x}{y-5}$  =  $\frac{13}{14}$ we get,
$\Rightarrow 13y=15x..............\left(i\right)$ and
 $14x=13(y-5)$
$\Rightarrow 14x=13y-\mathrm{65............}\left(ii\right)$
Substituting the value of (i) in (ii) we get,
$\Rightarrow 14x=15x-65$.
$x=65$
Substitute the value of x in (i)
$\Rightarrow 13y=15\times 65$
$y=15\times 5=75$
But Ankur lost 5 kg 
$\therefore$ Ankur's present weight is $(y-5)=(75-5)=70kg$

Ravi' Share: 1 Mark
Rani's Share: 1 Mark
Steps: 2 Marks
Let the share of Ravi and Rani be x and y respectively.
Total Profit = Rs. 40,000
Ratio of investment of Ravi to Rani = 2:3
Total parts of profit = 2+3 =5 
 

$x=\frac{2}{5}\times 40000$ = Rs. 16000

$y=\frac{3}{5}\times 40000$ = Rs. 24000

Share of Ravi in Profit is Rs. 16,000
Share of Rani in Profit is Rs. 24,000

Number of pink balls = 2 
Total number of balls = 2 + 3 + 5 = 10
$\therefore$ Ratio of pink balls to the total number of balls 
$=2:10=\frac{2}{10}=\frac{1}{5}=1:5$

If two quantities have different units then we cannot compare them by the method of ratio. A ratio is a method of comparison of two similar quantities by using the method of division.

If two ratios are equal or equivalent then we say that they are in proportion.

We know, to compare two quantities, the units must be the same.
So, here we either convert meter to a centimeter or vice-versa.
Given,
Length of the table = 2 m = 200 cm
Breadth = 50 cm
Hence, the required ratio
$=200:50=\frac{200}{50}=\frac{4}{1}=4:1$

Two ratios are said to be in proportion if they are equivalent or equal.
Here,
$\frac{4}{5}=\frac{4\times 3}{5\times 3}=\frac{12}{15}$
Hence, 4 : 5 :: 12 : 15, are in proportion.
Also product of 1st and 4th term should be equal to product of 2nd and 3rd term, which is only satisfied by 4 : 5 :: 12 : 15, i.e.,
$4\times 15=5\times 12=60$.
For rest of them the product of 1st and 4th term is not equal to the product of 2nd and 3rd term.