Concept: 1 Mark
Application: 1 Mark
Steps: 1 Mark
Solution: 1 Mark
Let x and y be the weight of Meenakshi and Ankur has respectively.
The ratio of the weights of Meenakshi to Ankur  = 13:15
After exercising, ratio of the weights of Meenakshi to Ankur = x :( y-5) = 13:14
Comparing both $\frac{x}{y}$ =  $\frac{13}{15}$  and  $\frac{x}{y-5}$  =  $\frac{13}{14}$ we get,
$\Rightarrow 13y=15x..............\left(i\right)$ and
 $14x=13(y-5)$
$\Rightarrow 14x=13y-\mathrm{65............}\left(ii\right)$
Substituting the value of (i) in (ii) we get,
$\Rightarrow 14x=15x-65$.
$x=65$
Substitute the value of x in (i)
$\Rightarrow 13y=15\times 65$
$y=15\times 5=75$
But Ankur lost 5 kg 
$\therefore$ Ankur's present weight is $(y-5)=(75-5)=70kg$