Ratio And Proportion(6th Grade > Mathematics ) Questions and answers for exam Preparation

6th Grade > Mathematics

RATIO AND PROPORTION MCQs

Total Questions : 95 | Page 3 of 10 pages

Question 21. Shekhar made 96 runs in 6 overs while Nitish made 102 runs in 6 overs. Then pick the correct statement.

Shekhar's run rate was 16 runs per over
Nitish's run rate was 15 runs per over
Nitish's run rate was lesser than that of Shekhar
Shekhar's run rate was 26 runs per over

Discuss Question

Answer: Option D. -> Shekhar's run rate was 26 runs per over
:
D

Shekhar's run rate = \frac{96}{6} = 16 runs per over .

Nitish's run rate = \frac{102}{6} = 17 runs per over .

Hence Nitish's run rate is greater than that of Shekhar.

Question 22. The cost of 20 envelopes is ₹50. How many envelopes can be purchased for ₹10?

Discuss Question

Answer: Option D. -> 4
:
D
The cost of 20 envelopes = ₹50.

∴

The cost of one envelope

= \frac{50}{20}

= ₹ 2.5
One envelope costs ₹2.5.
So, for ₹10, the number of envelopes thatcan be purchased is equal to

\frac{10}{2.5} = 4

Question 23. Find the fourth proportion to 1.2, 1.6 and 7.2.

Discuss Question

Answer: Option D. -> 2.6
:
D
Let the fourth proportionbe

x

.
Then, 1.2,1.6, 7.2,

x

are in proportion.
Product of means = Product of extremes

\Rightarrow 1.6 \times 7.2 = x \times 1.2

\Rightarrow 1.2 x = 1.6 \times 7.2

\Rightarrow x = \frac{1.6 \times 7.2}{1.2}

\Rightarrow x = 9.6

Question 24. If two quantities have different units then we can compare them by using the method of ratio.

True
False

Discuss Question

Answer: Option B. -> False
:
B
If two quantities have different units then we cannot compare them by the method of ratio. A ratio is a method of comparison of two similar quantities by using the method of division.

Question 25. Which of the following ratios are in proportion?

2:3 and 4:5
4:5 and 12:15
3:1 and 9:1
3:4 and 6:4

Discuss Question

Answer: Option B. -> 4:5 and 12:15
:
B
Two ratios are said to be in proportion if they are equivalent or equal.
Here,

\frac{4}{5} = \frac{4 \times 3}{5 \times 3} = \frac{12}{15}

Hence,4 : 5 :: 12 : 15, are in proportion.
Also product of 1st and 4thterm should beequal toproduct of 2ndand 3rdterm, which is only satisfied by4 : 5 :: 12 : 15, i.e.,

4 \times 15 = 5 \times 12 = 60

.
For rest of them theproduct of 1st and 4thterm is notequal to the product of 2ndand 3rdterm.

Question 26. Sonia and Surjeet started a competition to see who can collect the most number of stamps. At the end of one month, the ratio of the stamps Sonia had to those that Surjeet had was 89 : 93. If Surjeet has 2325 stamps. How many stamps does Sonia have? [4 MARKS]

Discuss Question

:
Steps: 3 Marks
Answer: 1 Mark
Let x and y be the number of stamps Sonia and Surjeet haverespectively.
At the end of one month,
Ratio of the stamps of Sonia to Surjeet
= x : y = 89 : 93

\frac{x}{y} = \frac{89}{93}

x = y . \frac{89}{93}

Given: y = 2325

x = 2325 \times \frac{89}{93}

x = \frac{2325 \times 89}{93} = 2225

Hence Sonia has 2225 stamps.

Question 27. Neha's toy car can travel 288 meters in a minute while Vendetta's toy car can travel 24.48 kilometres in an hour. The ratio of the speed of the cars belonging to Neha and Vendetta is: [4 MARKS]

Discuss Question

:
Steps: 2 Marks
Answer: 2 Marks
Distance travelled by Neha's toy car in a minute = 288m
Speed of Neha's toy car = 288 m/min
Distance travelled by Vendetta'stoy car in an hour (60 minutes) = 24.48km= 24480m (

\Rightarrow

1km = 1000m)
Distance travelled by Vendetta's toy carin a minute=

24480 \div 60

= 408 m
Speed of Vendetta's toy car=408 m/min
The ratio of the speed of the cars belonging to Neha and Vendetta =288 : 408 =12 : 17

Question 28. There are 20 girls and 15 boys in a class. [3 MARKS]
a) What is the ratio of the number of boys to the number of girls?
b) What is the ratio of the number of girls to the total number of students in the class?
c) What is the ratio of the number of boys to the total number of students in the class?

Discuss Question

:
Each option: 1 Mark
Total number of students in class

= 20 + 15 = 35

(a) Ratio of number of boys to the number of girls

= 15 : 20 = \frac{15}{20} = \frac{3}{4}

Hence, ratio of number of boys to the number of girls is

3 : 4

(b) Ratio of number of girls to the total number of students

= 20 : 35 = \frac{20}{35} = \frac{4}{7}

Ratio of number of girls to the total number of students is

= 4 : 7

(c)Ratio of number of boys to the total number of students

= 15 : 35 = \frac{15}{35} = \frac{3}{7}

Ratio of number of boys to the total number of students is

= 3 : 7

Question 29. The length and breadth of a rectangular field are in the ratio 4 : 5. If the length is 20m, find the breadth of the field. [2 MARKS]

Discuss Question

:
Steps: 1 Mark
Solution: 1 Mark

Length (l) : Breadth (b) = 4 : 5

\Rightarrow \frac{l}{b} = \frac{4}{5}

Given:

l = 20 m

\Rightarrow \frac{20}{b} = \frac{4}{5}

\Rightarrow \frac{b}{20} = \frac{5}{4}

\Rightarrow b = \frac{5 \times 20}{4}

b = 5 \times 5 = 25

∴ Breadth of the field = 25 m

Question 30. Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find ratio of [3 MARKS]
a) Number of students liking football to number of students liking tennis
b) The number of students liking cricket to the total number of students

Discuss Question

:
Each Option: 1.5 Mark
Number of students liking tennis