Practical Geometry(6th Grade > Mathematics ) Questions and answers for exam Preparation

6th Grade > Mathematics

PRACTICAL GEOMETRY MCQs

Total Questions : 94 | Page 10 of 10 pages

It is not possible to draw the perpendicular bisector of a line segment using a protractor ruler with no markings on it.

True
False
$60^{\circ}$
$75^{\circ}$

Discuss Question

Answer: Option B. -> False
:
B

Take a line segment say AB. Make angles $60^{\circ}$ on both the ends such that the lines along those angles intersect at C. Taking AB as the base side, draw $30^{\circ}$ angle and a line along it such that it intersects AB at D. Point D bisects AB and $∠ A D B$ is $90^{\circ}$ . So, AD is the perpendicular bisector of AB.

Question 92.

Draw a line segment AB of length $6.4 c m$ . Mark a point C on the line segment such that $A C = 3 c m$ . It is impossible to copy line segment CB without using a ruler or a compass or a divider.

True
False
$60^{\circ}$
$75^{\circ}$

Discuss Question

Answer: Option B. -> False
:
B

It is possible to copy line segment CB without using a ruler or a compass or a divider by tracing it on another paper. It may not be that accurate, but it is possible.

Question 93.

Draw a circle with radius $4 c m$ and center P. Draw another circle of same radius and with center at Q such that it intersects the previous circle. Join PQ. Now join the points of intersection and name this line segment as AB. Mark the point of intersection of AB and PQ as O.

$∠$ AOP = __ $^{\circ}$