Pie Charts(Reasoning Aptitude > Data Interpretation ) Questions and answers for exam Preparation

Reasoning Aptitude > Data Interpretation

PIE CHARTS MCQs

Pie Graphs

Total Questions : 124 | Page 10 of 13 pages

Question 91. Directions (1 - 5): Based on the data given on the pie-chart. Solve the questions which follow :
Percentage Sales of different models of Computers in Kolkata in two different years . Given total sales in 1998 is 7890 and increase 16.5% in 1999.

What is the ratio between the Compaq sales in 1998 and those IBM in 1999?

0.94
1.06
1.13
0.89

Discuss Question

Answer: Option B. -> 1.06
Sale of Compaq in 1998,
= 21%
= $$\frac{7890\times21}{100}$$
=1657
Sales of IBM in 1999,
= 17%
= $$\frac{9191\times17}{100}$$
= 1562
Ratio = $$\frac{1657}{1562}$$ = 1.06
We have calculated total sales in 1999 is 9191 in question no. 1.

Question 92. Directions (1 - 5): Based on the data given on the pie-chart. Solve the questions which follow :
Percentage Sales of different models of Computers in Kolkata in two different years . Given total sales in 1998 is 7890 and increase 16.5% in 1999.

Which brand of computers among those shown, exhibited the second highest rate of growth in two years and had less sales in 1999 than 1998?

HP
Compaq
Samsung
All of These

Discuss Question

Answer: Option D. -> All of These
There is no percentage change in the given three company.Thus, All of these is the correct answer.

Question 93. Directions (1 - 5): Based on the data given on the pie-chart. Solve the questions which follow :
Percentage Sales of different models of Computers in Kolkata in two different years . Given total sales in 1998 is 7890 and increase 16.5% in 1999.

For which brand of computers, did the sales increase the maximum in terms of absolute value between the two years?

IBM
Samsung
HP
Compaq

Discuss Question

Answer: Option D. -> Compaq
The maximum increase in sales is of Compaq which is 4%. Thus, it will got maximum absolute value too.

Question 94. Directions (1 - 5): Based on the data given on the pie-chart. Solve the questions which follow :
Percentage Sales of different models of Computers in Kolkata in two different years . Given total sales in 1998 is 7890 and increase 16.5% in 1999.

IBM's sales in 1998 is what percentage of the sales of Samsung in 1999?

46.34%
52.34%
57%
60.8%

Discuss Question

Answer: Option D. -> 60.8%
IBM's sales in 1998
= 17% of 7890
= 1341
Samsung sales in 1999
= 24% of 9191
= 2205
∴ Required answer
= $$\frac{1341}{2205}\times100$$
= 60.8%

Question 95. Directions (1 - 5): Refer to the pie-chart and the table carefully and answer the given question.

What is the central angles corresponding to the total number of cellular phones (both Nokia and Samsung) sold by store S?

99.2°
93.6°
105.6°
97.4°

Discuss Question

Answer: Option B. -> 93.6°
Store
Nokia Cellular Phones
Samsung Cellular Phones
Total Number of Cellular Phones
P
896
672
1568
Q
840
280
1120
R
1120
896
2016
S
1568
1344
2912
T
448
1792
2240
U
704
640
1344
Percentage of cellular phones (both Nokia and Samsung) sold by Store S = 26%
∴ Required central angle
= $$\frac{26}{100}$$ × 360
= 93.6°

Question 96. Directions (1 - 5): Refer to the pie-chart and the table carefully and answer the given question.

The total number of cellular phones (both Nokia and Samsung) sold by store Q increased by 15% from October to November and the same of cellular phones sold by store T increased by 5% from October to November. What was the total number of cellular phones sold by store Q and T together in November?

3540
3720
3640
3420

Discuss Question

Answer: Option C. -> 3640
Store
Nokia Cellular Phones
Samsung Cellular Phones
Total Number of Cellular Phones
P
896
672
1568
Q
840
280
1120
R
1120
896
2016
S
1568
1344
2912
T
448
1792
2240
U
704
640
1344
Number of cellular phones (both Nokia and Samsung) sold by store Q in October
= 11200 × $$\frac{10}{100}$$
= 1120
∵ Number of cellular phones (both Nokia and Samsung) sold by store Q in November
= 1120 × $$\frac{115}{100}$$
= 1288
Number of cellular phones (both Nokia and Samsung) sold by store T in October
= 11200 × $$\frac{20}{100}$$
= 2240
∵ Number of cellular phones (both Nokia and Samsung) sold by store T in November
= 2240 × $$\frac{105}{100}$$
= 2352
∵ Total number of cellular phones (both Nokia and Samsung) sold by Q and T together in November
= 1288 + 2352
= 3640

Question 97. Directions (1 - 5): Refer to the pie-chart and the table carefully and answer the given question.

The number of Nokia cellular phones sold by store R is what percent more than that of Samsung cellular phones sold by store P and Q together?

$$23\frac{1}{17}$$ %
$$19\frac{5}{17}$$ %
$$18\frac{3}{17}$$ %
$$17\frac{11}{17}$$ %

Discuss Question

Answer: Option D. -> $$17\frac{11}{17}$$ %
Store
Nokia Cellular Phones
Samsung Cellular Phones
Total Number of Cellular Phones
P
896
672
1568
Q
840
280
1120
R
1120
896
2016
S
1568
1344
2912
T
448
1792
2240
U
704
640
1344
Number of Nokia phones sold by store R = 1120
Number of Samsung phones sold by store P and Q together
= 672 + 280
= 952
$$\eqalign{
& \therefore \text{Required percentage} \cr
& = \frac{1120-952}{952}\times100 \cr
& = \frac{16800}{952}\% \cr
& = \frac{300}{17}\% \cr
& = 17\frac{11}{17}\% \text{ more} \cr} $$

Question 98. Directions (1 - 5): Refer to the pie-chart and the table carefully and answer the given question.

What is the average of Nokia cellular phones sold by store P, R, S and T together?

1008
1048
984
1006

Discuss Question

Answer: Option A. -> 1008
Store
Nokia Cellular Phones
Samsung Cellular Phones
Total Number of Cellular Phones
P
896
672
1568
Q
840
280
1120
R
1120
896
2016
S
1568
1344
2912
T
448
1792
2240
U
704
640
1344
Total Nokia Phone sold by stores P, R, S and T
= 896 + 1120 + 1568 + 448
= 4032
∴ Required average
= $$\frac{4032}{4}$$
= 1008

Question 99. Directions (1 - 5): Refer to the pie-chart and the table carefully and answer the given question.

What is the ratio of the number of Nokia cellular phones sold by store S to the Samsung cellular phones sold by store T and U together?

43 : 72
49 : 76
43 : 76
49 : 72

Discuss Question

Answer: Option B. -> 49 : 76
Store
Nokia Cellular Phones
Samsung Cellular Phones
Total Number of Cellular Phones
P
896
672
1568
Q
840
280
1120
R
1120
896
2016
S
1568
1344
2912
T
448
1792
2240
U
704
640
1344
Number of Nokia phones sold by store S = 1568
Number of Samsung Phones sold by store T and U together
= 1792 + 640
= 2432
$$\eqalign{
& \therefore \text{ Required ratio} \cr
& = \frac{1568}{2432} \cr
& = \frac{49}{76} \cr
& = 49:76 \cr} $$

Question 100. Direction (1 - 5): Study the pie-chart given below carefully and answer the questions that follow.

What is the total number of students having IB as specialisation?

1520
1280
1360
1120

Discuss Question

Answer: Option A. -> 1520
Number of students in various specialisations:
$$\eqalign{
& \text{IB → } \frac{19}{100}\times8000 = 1520 \cr
& \text{IR → } \frac{16}{100}\times8000 = 1280 \cr
& \text{Finance → } \frac{12}{100}\times8000 = 960 \cr
& \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr
& \text{IT → } \frac{17}{100}\times8000 = 1360 \cr
& \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$
Number of those having IB as specialisation = 1520