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Quantitative Aptitude

MIXTURES AND ALLEGATIONS MCQs

Alligations And Mixtures

Total Questions : 245 | Page 9 of 25 pages
Question 81. A container contains 50 litres of milk. From that 8 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
  1.    28.21 litres
  2.    24.52 litres
  3.    25.14 litres
  4.    29.63 litres
 Discuss Question
Answer: Option D. -> 29.63 litres

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg   Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg   Therefore, Copper in mixture =  4 5 + 5 6 = 49 30  kg   and  Zinc in the mixture = 16 5 + 25 6 = 221 30 kg   Therefore the required ratio = 49 : 221


Question 82. 4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:
  1.    49 : 221
  2.    None of these
  3.    39:231
  4.    94:181
 Discuss Question
Answer: Option A. -> 49 : 221

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg   Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg   Therefore, Copper in mixture =  4 5 + 5 6 = 49 30  kg   and  Zinc in the mixture = 16 5 + 25 6 = 221 30 kg   Therefore the required ratio = 49 : 221


Question 83. A milkman claims to sell milk at its cost price, still, he is making a profit of 30% since he has mixed some amount of water in the milk. What is the % of milk in the mixture?
  1.    76.92%
  2.    71.02%
  3.    63.22%
  4.    86.42%
 Discuss Question
Answer: Option A. -> 76.92%

Let the milk he bought is 1000 ml Let C.P of 1000 ml is Rs. 100 Here let he is mixing K ml of water He is getting 30% profit => Now, the selling price is also Rs. 100 for 1000 ml => 100 : K% = 100 : 30 10 : 3 is ratio of milk to water => Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%


Question 84. How many liters of oil at Rs.40 per liter should be mixed with 240 liters of a second variety of oil at Rs.60 per liter so as to get a maximum whose cost is Rs.52 per liter?
  1.    180
  2.    110
  3.    120
  4.    160
 Discuss Question
Answer: Option D. -> 160

Applying Allegation Method to first calculate the ratio in which they have to be mixed: = 8 : 12 = 2 : 3
Thus, the two varieties of oil should be mixed in the ratio 2 : 3. So, if 240 liters of the second variety are taken, then 160 liters of the first variety should be taken


Question 85. The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?
  1.    6 ml
  2.    11 ml
  3.    15 ml
  4.    9 ml
 Discuss Question
Answer: Option A. -> 6 ml

Let us assume that the lotion has 50% alcohol and 50% water.ratio = 1:1As the total solution is 9mlalcohol = water = 4.5mlNow if we want the quantity of alcohol = 30%The quantity of water = 70%The new ratio = 3:7Let x ml of water be addedWe get, 4 . 5 4 . 5 + x   =   3 7 => x=6Hence 6ml of water is added.


Question 86. Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.
  1.    7:3
  2.    9:1
  3.    3:7
  4.    1:9
 Discuss Question
Answer: Option A. -> 7:3

Ratio of Milk and water in a vessel A is 4 : 1   Ratio of Milk and water in a vessel B is 3 : 2   Ratio of only milk in vessel A = 4 : 5   Ratio of only milk in vessel B = 3 : 5   Let 'x' be the quantity of milk in vessel C   Now as equal quantities are taken out from both vessels A & B   => 4/5     :     3/5               x   3/5-x          x - 4/5   => 3 5 - x x - 4 5  = 1 1  (equal quantities)   => x = 7/10   Therefore, quantity of milk in vessel C  = 7   => Water quantity = 10 - 7 = 3   Hence the ratio of milk & water in vessel 3 is 7 : 3


Question 87. In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture?
  1.    2:1
  2.    1:1
  3.    1:2
  4.    3:1
 Discuss Question
Answer: Option B. -> 1:1

Quantity of alohol in the mixture = 40 x 5/8 = 25 lit Quantity of water = 40 - 25 = 15 lit According to question, Required ratio =  20   -   40   x   20 100   x   5 8 15   -   40   x   20 100   x   3 8   +   40   x   20 100   =   20 15   -   3   +   8   =   1   :   1


Question 88. A mixture of 70 litres of Fruit Juice and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12.5% water?
  1.    1 lit
  2.    4 lit
  3.    3 lit
  4.    2 lit
 Discuss Question
Answer: Option D. -> 2 lit

Quantity of fruit juice in the mixture = 70 - [70 x (10/100) ]= 63 litres.   After adding water, juice would form 87.5% of the mixture.   Hence, if quantity of mixture after adding x liters of water, [(87.5) /100 ]*x = 63 => x = 72    Hence 72 - 70 = 2 litres of water must be added.


Question 89. The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture?
  1.    4:3
  2.    2:3
  3.    3:2
  4.    3:4
 Discuss Question
Answer: Option C. -> 3:2

Concentration of glucose are in the ratio = 1 2 : 3 5 : 4 5 Quantity of glucose taken from A = 1 liter out of 2 Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit Quantity of glucose taken from C = 0.8 lit So, total quantity of glucose taken from A,B and C = 3.6 lit So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit Ratio of glucose to alcohol = 3.6/2.4 = 3:2


Question 90. One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.
  1.    26 %
  2.    27 %
  3.    21 %
  4.    29 %
 Discuss Question
Answer: Option B. -> 27 %

Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %


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