Mixtures And Allegations(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

MIXTURES AND ALLEGATIONS MCQs

Alligations And Mixtures

Total Questions : 245 | Page 11 of 25 pages

Question 101. From the 50 liters of milk, 5 liters of milk is taken out and after it 5 liters of water is added to the rest amount of milk. Again 5 liters of milk and water is drawn out and it was replaced by 5 liters of water. If this process is continued similarly for the third time, the amount of milk left after the third replacement:

40.5L
36.45L
45L
42.5L

Discuss Question

Answer: Option B. -> 36.45L

General Formula: Final or reduced concentration = initial concentration x 1 - a m o u n t b e i n g r e p l a c e d i n e a c h o p e r a t i o n t o t a l a m o u n t n where n is the number of times the same operation is being repeated. The "amount being replaced" could be pure or mixture as per the case. similarly ,"total amount" could also be either pure or mixture. Here amount being replaced denotes the quantity which is to be withdrawn in each time. Therefore, 50 × 1 - 5 50 3 = 36.45 L

Question 102. In a mixture of 240 lt. water is 20% and rest is Milk. What quantity of mixture should be taken out and replaced with water so that water becomes 40%?

55 lit
45 lit
60 lit
50 lit

Discuss Question

Answer: Option C. -> 60 lit

For these type of problems, Quantity of Diesel remained = q 1 - p q n Here p = 12 , q = 120 => 120 1 - 12 120 3 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

Question 103. A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container?

87.51 lit
87.62 lit
88.01 lit
87.48 lit

Discuss Question

Answer: Option D. -> 87.48 lit

For these type of problems, Quantity of Diesel remained = q 1 - p q n Here p = 12 , q = 120 => 120 1 - 12 120 3 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

Question 104. In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

Discuss Question

Answer: Option D. -> 60

Let M litres milk be added => 60 + M 40 = 3 1 => 60 + M = 120 => M = 60 lit.

Question 105. Two bottles contains mixture of milk and water. First bottle contains 64% milk and second bottle contains 26% water. In what ratio these two mixtures are mixed so that new mixture contains 68% milk?

1 : 2
3 : 2
2 : 1
2 : 3

Discuss Question

Answer: Option B. -> 3 : 2

% of milk in first bottle = 64% % of milk in second bottle = 100 - 26 = 74% Now, ATQ 64% 74% 68% 6 4 Hence, by using allegation method, Required ratio = 3 : 2

Question 106. If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain?

Discuss Question

Answer: Option C. -> 25%

He has gain = 15 - 12 = 3,Gain% = (3/12) x 100 = (100/4) = 25.He has 25% gain.

Question 107. Shiva purchased 280 kg of Rice at the rate of 15.60/kg and mixed it with 120 kg of rice purchased at the rate of 14.40/kg. He wants to earn a profit of Rs. 10.45 per kg by selling it. What should be the selling price of the mix per kg?

Rs. 22.18
Rs. 25.69
Rs. 26.94
Rs. 27.54

Discuss Question

Answer: Option B. -> Rs. 25.69

Rate of rice of quantity 280 kg = Rs. 15.60/kg Rate of rice of quantity 120 kg = Rs. 14.40/kg He want to earn a profit of Rs. 10.45/kg Rate of Mix to sell to get profit of 10.45 = 280 x 15 . 60 + 120 x 14 . 40 280 + 120 + 10 . 45 4368 + 1728 400 + 10 . 45 = > 15 . 24 + 10 . 45 = 25 . 69

Question 108. Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him?

14.92
16.38
13.98
15.84

Discuss Question

Answer: Option B. -> 16.38

Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg. Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25) => Total cost of the mixture = Rs. 630 Total kgs of the mixture = 30 + 20 = 50kg Cost of mixture/kg = 630/50 = 12.6/kg To make 30% of profit => Selling price for manideep = 12.6 + 30% x 12.6 => Selling price for manideep = 12.6 + 3.78 = 16.38/kg.

Question 109. In what ratio should two varieties of tea at Rs. 60 per kg and Rs.120 per kg be mixed together so that by selling the mixture at Rs.96 per kg, a profit of Rs.20% is obtained?

Discuss Question

Answer: Option B. -> 2:1

Question 110. How much pepsi at Rs.6 a litre is added to 15 litre of 'dew' at Rs. 10 a litre so that the price of the mixture be Rs.9 a litre?