One type of liquid contains 25 % of benzene, the other contains 30% of benzene.

Question

One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

Options:

A . 26 %

B . 27 %

C . 21 %

D . 29 %

Answer: Option B

Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %

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