Mixtures And Allegations(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

MIXTURES AND ALLEGATIONS MCQs

Alligations And Mixtures

Total Questions : 245 | Page 8 of 25 pages

Question 71. In a mixture of milk and water, there is only 26% water. After replacing the mixture with 7 liters of pure milk , the percentage of milk in the mixture become 76%. The quantity of mixture is:

38 liters
65 liters
91 liters
None of these

Discuss Question

Answer: Option C. -> 91 liters

Milk Water 74% 26% (initially) 76% 24% ( after replacement) Left amount = Initial amount 1 - r e p l a c e d a m o u n t t o t a l a m o u n t 24 = 26 1 - 7 k => k = 91

Question 72. From a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The initial amount of wine in the container was:

100 liters
75 liters
150 liters
120 liters

Discuss Question

Answer: Option D. -> 120 liters

W i n e ( l e f t ) W a t e r ( a d d e d ) = 343 169 It means W i n e ( l e f t ) W i n e ( i n i t i a l a m o u n t ) = 343 512 ? 343 + 169 = 512 Thus , 343 x = 512 x 1 - 15 K 3 ? 343 512 = 7 8 3 = 1 - 15 k 3 => K = 120 Thus the initial amount of wine was 120 liters.

Question 73. Ratio of water and milk in a container is 2 : 3. If 40 liter mixture removed from the container and same quantity of milk is added to it then the ratio of water to milk becomes 1 : 4. Find the initial quantity of mixture?

80 lit
85 lit
75 lit
90 lit

Discuss Question

Answer: Option A. -> 80 lit

From the given data, let the initial quantity of the mixture = 5x Then, 2 x - 16 3 x - 24 + 40 = 1 4 8 x - 64 = 3 x + 16 5 x = 80 x = 16 lit Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

Question 74. A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

58 l
62 l
50 l
65 l

Discuss Question

Answer: Option C. -> 50 l

Let the tin contain 5x litres of liquids 5 x - 45 x 4 5 5 x - 45 x 1 5 + 45 = 2 5 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 1 5 + 45 = 50 litres.

Question 75. From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

150 litres
120 litres
100 litres
75 litres

Discuss Question

Answer: Option B. -> 120 litres

w i n e ( l e f t ) w i n e ( a d d e d ) = 343 169 It means w i n e ( l e f t ) w i n e ( i n i t i a l a m o u n t ) = 343 512 (since 343 + 169 = 512) Thus, 343 x = 512 x 1 - 15 k 3 343 512 = 7 8 3 = 1 - 15 k 3 1 - 15 k = 7 8 = 1 - 1 8 Thus the initial amount of wine was 120 liters.

Question 76. In a 48 ltr mixture, the ratio of milk and water is 5:3. How much water should be added in the mixture so as the ratio will become 3:5?

8 lit
16 lit
24 lit
32 lit

Discuss Question

Answer: Option D. -> 32 lit

Given mixture = 48 lit Milk in it = 48 x 5/8 = 30 lit => Water in it = 48 - 30 = 18 lit Let 'L' lit of water is added to make the ratio as 3:5 => 30/(18+L) = 3/5 => 150 = 54 + 3L => L = 32 lit.

Question 77. In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water? (Weight in gm)

Discuss Question

Answer: Option A. -> 80%

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm. After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm. So % of water = 100 x 60/75 = 80%.

Question 78. A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

1 kg
None of these
1.25 kg
1.5 kg

Discuss Question

Answer: Option C. -> 1.25 kg

Let the initial amount of honey in the jar was K, then 512 = K 1 - 1 5 4 ? 20 % = 20 100 = 1 5 or 512 = K 4 5 4 Therefore, K = 1250 Hence initially the honey in the jar= 1.25 kg

Question 79. A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

1 : 10
10 : 1
9 : 11
11 : 9

Discuss Question

Answer: Option A. -> 1 : 10

Customer ratio of Milk and Water is given by Milk :: Water 6.4 0 8 1 + 3 8 = 64 11 64 11 64 10 - 64 11 => Milk : Water = 110 : 11 = 10 : 1 Therefore, the proportionate of Water to Milk for Customer is 1 : 10

Question 80. A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal.