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Question
4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:
Options:
A .  49 : 221
B .  None of these
C .  39:231
D .  94:181
Answer: Option A

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg   Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg   Therefore, Copper in mixture =  4 5 + 5 6 = 49 30  kg   and  Zinc in the mixture = 16 5 + 25 6 = 221 30 kg   Therefore the required ratio = 49 : 221



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