Reasoning Aptitude
LETTER AND SYMBOL SERIES MCQs
From choice (1), B > E definitely follows, but we cannot determine the relationship between A and D.From choice (2), A > D and E < B definitely follows.From choice (3), we cannot determine relationships between A and D and E and B.From choice (4), A is either greater than or equal to D.We cannot say definitely A > D.
From choice(1), Q > M and R > N definitely follows.From choice(2), Q ≥ M, we cannot say definitely Q > M.From choice(3), Q ≥ M, we cannot say definitely Q > M.From choice(4), Q ≤ M < then Q > M does not follow.
In the above sequence,4+2 @+2 7+2,$+2, E+2, 9+2,>+2, ↓+2 ʘ+2,?+2, J+2,
G
From choice(1), P ≤ Q, we cannot say definitely P < Q.From choice (2), we cannot determine relation ship between P and Q.From choice (3), we cannot determine relation ship between P and Q.From choice (4), P < Q and S > R definitely follows.
B,C and H are the three letters which are followed by a digit but not immediately preceded by a consonant.
The following are the expressions which the symbols are used.A $ B => A < B.A © B => A > B.A @ B => A ≤ B.A * B => A ≥ B.A # B => A = B.
G $ I => G < I.I * K => I ≥ K.K # M => K = M.M $ O => M < O.By combining the above statements We get,G < I ≥ K = M < O.Conclusion I: I * M => I ≥ M, follows.Conclusion II: K $ O => K < O, follows.Conclusion III: G © K => G > K, does not follow.Conclusion IV: I @ M => I ≤ M, does not follow.
Only I and II follow.
> and ʘ are the only symbols which are proceeded by an alphabet and followed by a digit.
R K 5 9 # B 2 % * E ? A 8 L $ I 4 S V 7 ! C 6 N @ H 1 3 & DThe sequence is5#2, *?8, $4V, ___The logic is as follows.5+2#+22+2, *+2?+28+2, $+24+2V+2, i+26+2@.
In choice (3), R > P, hence R ≤ P definitely follows.
The following are the expressions which the symbols are used.A $ B => A < B.A © B => A > B.A @ B => A ≤ B.A * B => A ≥ B.A # B => A = B.
P @ Q => P ≤ Q.Q # R => Q = R.R $ S => R < S.S © T => S > T.By combining the above statements We get,P ≤ Q = R < S > TConclusion I: P $ T => P < T, does not follow.Conclusion II: R # P => R = P, does not follow.Conclusion III: T $ R => T < R, does not follow.Conclusion IV: R © P => R > P, does not follow.But conclusion II and IV are contradictory to each other.
Either II or IV follows