Reasoning Aptitude
LETTER AND SYMBOL SERIES MCQs
The sequence is 86V, 2KN, ?19, __.The logic is as follows
8+3 6+3 V+3, 2+3 K+3 N+3 , ?+3 1+3 9+3, E+3 8+3 6,Hence, E86 is the next term.
The given expression(10 - 5) / 50 * (25 * 5) / 40becomes(10 + 5 ) * 50 - (25 - 5) * 40Using BODMAS rule,(10 + 5 ) * 50 - (25 - 5) * 40= 15 * 50 - 20 * 40= 750 - 800= -50
'+' means '*', '*' means '-', '-' means '/' and '/' means '+'.The given expression is9 + 4 - 6 * 6 / 8On converting this expression as per the directions, we get the expression9 * 4 / 6 - 6 + 8We simplify this expression using BODMAS rule,9 * 4 / 6 - 6 + 8 = 36 / 6 - 6 + 8 = 8.
'+' means '/', '/' means '*', '*' means '-', '-' means '+'.The given expression is5 * 10 - 15 / 20 + 25 / 30According to the given direction, the above expression becomes5 - 10 + 15 * 20 / 25 * 30Using BODMAS rule,5 - 10 + 15 * 20 / 25 * 30= -5 + 300 / 25 * 30= -5 + 12 * 30= 355.
The given expression is10 + 10 * 10 - 10 / 10As per the directions, it becomes
10 * 10 - 10 / 10 + 10Using BODMAS rule,10 * 10 - 10 / 10 + 10= 100 - 1 + 10= 109.
The given expression16 * 4 / 4 + 14 - 2becomes16 - 4 + 4 * 14 / 2as per the given directions.Using BODMAS rule,16 - 4 + 4 * 14 / 2= 12 + 56 / 2= 12 + 28= 40
a + b means a > b, a - b means a = b, a = b means a > b, a * b means a A > BB * C => B C B D which can not be definitely determined because A could be either greater than, less than or equal to D.Conclusion (II): A = C => A > CWhich can not be determined as A can be less than C.
P @ Q => P < QP # Q => P ≥ QP $ Q => P = QP © Q => P ≤ QP % Q => P > QThe Statement isA % B => A > BB # C => B ≥ CC @ D => C < DD % E => D > EBy Combining the aboveStatements we getA > B ≥ C < D > E.Conclusion I: A % C => A > C follows.Conclusion II: D @ A => D < A, doesnot follow.Conclusion III: B # E => B ≥ E, doesnot follow.
Only I follow.
p ۞ q means p > qp @ q means p < qp # q means p ≥ qp ∆ q means p ≤ qp □ q means p = qThe statement is (i) k □ l (ii) l ∆ m (iii) m @ ni.e, k = l, l ≤ m, m < n=> k = l ≤ m < nConclusion I: l @ n => l < n is trueHence I follows.Conclusion II: m # k => m ≥ k is true.Hence II follows.
a + b means a > b, a - b means a = b, a = b means a ≥ b, a * b means a ≤ b and a / b means a < b.According to the Statement:P / Q => P < QQ - R => Q = RR + S => R > SP < Q = R > SConclusion (i): P = S => P ≥ S, cannot be definitely determined because P can be less than S.Conclusion (ii): p / R => P < RAs P < Q and Q = RP < R follows.