Reasoning Aptitude
LETTER AND SYMBOL SERIES MCQs
a £ b means a ≤ ba $ b means a ≥ ba ↑ b means a < ba â— b means a > ba â–² b means a = bThe statement is (i) e £ f, (ii) f ↑ g (iii) e â–² hi.e, e ≤ f, f < g, e = h=> g > h ≥ e = hConclusion I: f $ h => f ≥ h is true.Hence, I follows.Conclusion II: g â— e = g > e is trueHence, II follows.
p ۞ q means p > qp @ q means p < qp # q means p ≥ qp ∆ q means p ≤ qp □ q means p = qThe statement is (i) x □ y (ii) y @ z (iii) w ۞ xi.e, x ≤ y < z, w > x=> x ≤ y < z and x < wConclusion I: w ۞ y => w > y is true.Hence, I follows.Conclusion II: x @ z => x < z is true.Hence II follows.
P @ Q => P < QP # Q => P ≥ QP $ Q => P = QP © Q => P ≤ QP % Q => P > QM # N => M ≥ N.O @ N => O < N.P © O => P ≤ O.P # Q => P ≥ Q.By combining the above statement we get,M ≥ N > O ≥ P ≥ QConclusion I: O @ M => O < M, follows.Conclusion II: N % Q => N > Q, follows.Conclusion III: O # Q => O ≥ Q, follows.All follow.
a + b means a > b, a - b means a = b, a = b means a ≥ b, a * b means a ≤ b and a / b means a < b.According to the statementM * N => M ≤ NO = N => O ≥ N => N ≤ OO * P => O ≤ PM ≤ N ≤ O ≤ PConclusion (i): M * P => M ≤ P, followsConclusion (ii): O = M => O ≥ M, follows
By replacing question mark with '>' symbol. We get,E ≤ F ≥ G > H = I ≥ K.From the above, F > I and G > K definitely follow.
By replacing question mark with '≥' symbol. We get,K > M ≥ N ≥ O ≥ P ≥ Q.From the above 'K > O' and 'N ≥ Q' definitely follow.
By replacing question mark with '>' symbol we get,T ≥ X > Y ≥ Z > V ≤ W.From the above 'X > V' and 'Z < T' definitely follow.
By replacing with any symbol we can not determine definite relation between 'F and C' and 'B and E'
By replacing question mark with '>' symbol we get,T ≥ X > Y ≥ Z > V ≤ W.From the above 'X > V' and 'Z < T' definitely follow.
Using the correct symbols, we have:
Given expression = 20 + 8 - 8 / 4 * 2
= 20 + 8 - 2 * 2 = 20 + 8 - 4 = 24.