Letter And Symbol Series(Reasoning Aptitude ) Questions and answers for exam Preparation

Reasoning Aptitude

LETTER AND SYMBOL SERIES MCQs

Total Questions : 150 | Page 12 of 15 pages

Question 111. If * means -, + means /, - means * and , means +, then
15 - 2 / 900 + 90 * 100 = ?

190
180
90
0
None of these

Discuss Question

Answer: Option E. -> None of these

Using the correct symbols, we have:
Given expression = 15 * 2 + 900 / 90 - 100
= 15 * 2 + 10 - 100
= 30 + 10 - 100
= - 60

Question 112. If + means -, - means *, * means /, / means +, then 15 * 3 / 15 + 5 - 2 = ?

0
6
10
20
None of these

Discuss Question

Answer: Option C. -> 10

Using the correct symbols, we have :
Given expression = 15 / 3 + 15 * 2
= 5 + 15 - 5 * 2
= 5 + 15 -10
= 10

Question 113. If + means /, - means *, / means -, * means +, what will be the value of 8 + 6 / 4 - 7 * 3 ?

- 71 / 3
- 23 / 2
12
14
None of these

Discuss Question

Answer: Option A. -> - 71 / 3

Using the correct symbols, we have:
Given expression = 8 / 6 - 4 * 7 + 3
= (4 / 3) - 4 * 7 + 3
= (4 / 3) - 28 + 3
= - 71 / 3

Question 114. If P denotes +, Q denotes *, R denotes / and S denotes -, then
18 Q 12 P 4 R 5 S 6 = ?

36
53
59
65
None of these

Discuss Question

Answer: Option B. -> 53

Using the correct symbols, we have:
Given expression = 18 * 12 / 4 + 5 - 6
= 18 * 3 + 5 - 6
= 53

Question 115. In a certain code language, '+' means '/', '/' means '*', '*' means '-', '-' means '+'.44 - 11 / 2 * 6 / 6 + 2 - 12

Discuss Question

Answer: Option B. -> 60

As per the given expression44 - 11 / 2 * 6 / 6 + 2 - 12becomes44 + 11 * 2 - 6 * 6 / 2 + 12.Using BODMAS rule,44 + 11 * 2 - 6 * 6 / 2 + 12= 44 + 22 - 36 / 2 + 12= 66 - 18 + 12= 60.

Question 116. In a certain code language, '+' means '/', '/' means '*', '*' means '-', '-' means '+'.(10 - 2 * 3) / (4 - 5 * 8) * (2 - 3) / 2

90
0
-1
-34
100

Discuss Question

Answer: Option C. -> -1

The given expression(10 - 2 * 3) / (4 - 5 * 8) * (2 - 3) / 2
becomes(10 + 2 - 3) * (4 + 5 - 8) - (2 + 3) * 2.
Using BODMAS rule,(10 + 2 - 3) * (4 + 5 - 8) - (2 + 3) * 2= 9 * 1 - 5 * 2= 9 - 10= -1

Question 117. In a certain code language, '+' means '*', '*' means '-', '-' means '/' and '/' means '+'.16 - 2 + 4 / 16 - 8 * 2

Discuss Question

Answer: Option E. -> 32

As per the given expression,16 - 2 + 4 / 16 - 8 * 2becomes16 / 2 * 4 + 16 / 8 - 2Using BODMAS rule,16 / 2 * 4 + 16 / 8 - 2= 8 * 4 + 2 - 2= 32 + 0= 32

Question 118. In a certain code language, '+' means '/', '/' means '*', '*' means '-', '-' means '+'.(13 - 5 * 8 + 4) * (5 - 6 + 12 * 3) / (4 + 2)

7.5
29
27
-2.5
11

Discuss Question

Answer: Option E. -> 11

The given expression(13 - 5 * 8 + 4) * (5 - 6 + 12 * 3) / (4 + 2)becomes(13 + 5 - 8 / 4) - (5 + 6 / 12 - 3) * (4 / 2)Using BODMAS rule,(13 + 5 - 8 / 4) - (5 + 6 / 12 - 3) * (4 / 2)= (18 - 2) - [5 + (1/2) - 3] * 2= 16 - (5/2) * 2= 11

Question 119. In a certain code language, '+' means '*', '*' means '-', '-' means '/' and '/' means '+'.2 / 4 + 8 - 16 * 32 / 64 * 128 / 256

Discuss Question

Answer: Option B. -> 164

As per the given expression2 / 4 + 8 - 16 * 32 / 64 * 128 / 256
becomes2 + 4 * 8 / 16 - 32 + 64 - 128 + 256
Using BODMAS rule,2 + 4 * 8 / 16 - 32 + 64 - 128 + 256= 2 + 32 / 16 + 32 + 128= 2 + 2 + 160= 164.

Question 120. p Ûž q means p is neither less than nor equal to q.p @ q means p is neither greater than nor equal to q.p # q means p is not less than q.p âˆ† q means p is not greater than q.p â–¡ q means p is neither smaller nor greater than q.Statement: a â–¡ b, c âˆ† d, b Ûž cConclusions: I. a Ûž c II. b # d

if only conclusion (I) follows
if only conclusion (II) follows
if both conclusions (I) and (II) follows
if neither (I) nor (II) follows
if either conclusion (I) or (II) follows

Discuss Question

Answer: Option A. -> if only conclusion (I) follows

p Ûž q means p > qp @ q means p < qp # q means p â‰¥ qp âˆ† q means p â‰¤ qp â–¡ q means p = qThe Statement is (i) a â–¡ b (ii) c âˆ† d (iii) b Ûž ci.e. a = b, c â‰¤ d, b > c=> a = b > cConclusion I: a Ûž c => a > c is trueHence, I follows.Conclusion II: b # d => b â‰¥ d cannot be concludedHence, II does not follow.