7th Grade > Mathematics
FRACTIONS AND DECIMALS MCQs
Fractions, Decimals
Total Questions : 227
| Page 8 of 23 pages
Answer: Option B. -> 161
:
B
(124 -12 +3616 -116 +28)
=64−12+5416−116+28
Taking LCM of denominators and solving,
24−8+54−1+416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.
:
B
(124 -12 +3616 -116 +28)
=64−12+5416−116+28
Taking LCM of denominators and solving,
24−8+54−1+416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.
Answer: Option B. -> 7718
:
B
Given [514−25×559+(12+34)]
ApplyBODMAS rule to solve
= [214−(25×509)+54]
= [214−(209)+54]
Taking LCM of denominators, we have
189−80+4536=15436=7718
[514−25×559+(12+34)]=7718
:
B
Given [514−25×559+(12+34)]
ApplyBODMAS rule to solve
= [214−(25×509)+54]
= [214−(209)+54]
Taking LCM of denominators, we have
189−80+4536=15436=7718
[514−25×559+(12+34)]=7718
Answer: Option B. -> 7718
:
B
Given [514−25×559+(12+34)]
ApplyBODMAS rule to solve
= [214−(25×509)+54]
= [214−(209)+54]
Taking LCM of denominators, we have
189−80+4536=15436=7718
[514−25×559+(12+34)]=7718
:
B
Given [514−25×559+(12+34)]
ApplyBODMAS rule to solve
= [214−(25×509)+54]
= [214−(209)+54]
Taking LCM of denominators, we have
189−80+4536=15436=7718
[514−25×559+(12+34)]=7718
Answer: Option D. -> 0
:
D
Concentrate on numerator. The expression has '0' multiplied to it, and any numbermultiplied by'0' is '0'.
And 0 divided by any numberalways '0'.
Hence the answer is '0'.
:
D
Concentrate on numerator. The expression has '0' multiplied to it, and any numbermultiplied by'0' is '0'.
And 0 divided by any numberalways '0'.
Hence the answer is '0'.
Answer: Option C. -> 178 kg
:
C
First, let usdo the conversion of mixed fractions into improper fractions.
i.e 312=(2×3)+12=72
223=(3×2)+23=83, and
113=(3×1)+13=43
Total quantityof fruits=(72+83+43)kg
=72+4
=72+82 kg
=152 kg
When 152kg is divided among 4people,
each person's share =1524kg
=(152×14)kg
=158kg
=178kg
Hence, each person gets(178)kg of fruits.
:
C
First, let usdo the conversion of mixed fractions into improper fractions.
i.e 312=(2×3)+12=72
223=(3×2)+23=83, and
113=(3×1)+13=43
Total quantityof fruits=(72+83+43)kg
=72+4
=72+82 kg
=152 kg
When 152kg is divided among 4people,
each person's share =1524kg
=(152×14)kg
=158kg
=178kg
Hence, each person gets(178)kg of fruits.
Answer: Option B. -> 161
:
B
(124 -12 +3616 -116 +28)
=64−12+5416−116+28
Taking LCM of denominators and solving,
24−8+54−1+416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.
:
B
(124 -12 +3616 -116 +28)
=64−12+5416−116+28
Taking LCM of denominators and solving,
24−8+54−1+416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.
Answer: Option B. -> 392 km
:
B
Let the total distance to be covered =dkm
Then, 18×d = 56km
d = (56×8)km = 448km
Remaining distance= (448 - 56)km = 392km
:
B
Let the total distance to be covered =dkm
Then, 18×d = 56km
d = (56×8)km = 448km
Remaining distance= (448 - 56)km = 392km
Answer: Option B. -> 392 km
:
B
Let the total distance to be covered =dkm
Then, 18×d = 56km
d = (56×8)km = 448km
Remaining distance= (448 - 56)km = 392km
:
B
Let the total distance to be covered =dkm
Then, 18×d = 56km
d = (56×8)km = 448km
Remaining distance= (448 - 56)km = 392km
Answer: Option D. -> 8.5
:
D
52+73+94110×25×1256
=851256
=8512×65
=172=8.5
:
D
52+73+94110×25×1256
=851256
=8512×65
=172=8.5
:
Let the other fraction be x
Then, x×14=20
x=20×4=80